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stepan [7]
2 years ago
7

Which situation can be simulated by rolling a six-sided die once?

Mathematics
2 answers:
AleksandrR [38]2 years ago
8 0

Answer:

A. Selecting one person from a group of four boys and two girls.

Step-by-step explanation:

A dice has six sides and here we have six people we're trying to choose from. If each person is assigned a number on the dice rolling the dice once will pick out of the six of them.

kkurt [141]2 years ago
7 0

Answer:

A and D

Step-by-step explanation:

A is pretty obvious becuase there are four girls and two boyd which add up to six

Now D would be correct because you have two options so you can split it up 50/50 to get your answer!

HOPE this helps you!

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Please someone help me to prove this. ​
dem82 [27]
<h3><u>Answer</u> :</h3>

We know that,

\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}

\dag\bf\:sin2A=2sinA\:cosA

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>Now, Let's solve</u> !

\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}

\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}

\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}

\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}

\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}

\leadsto\:\bf{tan(A+B)}

5 0
3 years ago
Read 2 more answers
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is P(X=0) \approx 0.8659

The probability of at least 1 failure in a 24-hour day is P(X\geq 1 )\approx 0.3508

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

P(X)=\frac{e^{-\mu}\mu^x}{x!}

Let X be the number of failures of a testing instrument.

We know that the mean \mu = 0.018 failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is \mu=8\cdot 0.018=0.144

P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is \mu=24\cdot 0.018=0.432

P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508

3 0
3 years ago
Adam wrote a check for $38 to pay his monthly gas bill, but when balancing his checkbook, he accidently recorded it as a credit
Alex73 [517]
It would be $76 over, I hope this helps.
7 0
3 years ago
Read 2 more answers
There are four roads from A to B and five roads from B to C. In how mamy different ways can a person travel from A to C?
Lelu [443]

That would be 4 * 5 = 20 ways  answer.

3 0
3 years ago
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Https://www.linkedin.com/pulse/100-reasons-why-you-shouldnt-commit-sui cide-aaditya-thapa
Gekata [30.6K]

Answer:

9+10=21

bettttt

ima do it anyway

4 0
2 years ago
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