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miss Akunina [59]
3 years ago
11

Help me do my math please

Mathematics
2 answers:
Anestetic [448]3 years ago
5 0
A.58/11 c.61/20 d. 6 3/100
sergiy2304 [10]3 years ago
5 0
A.) 5 3/11 = 58/11

B.) 49/4 = 12 1/4

C.) 3 1/20 = 61/20

D.) 603/100 = 6 3/100

Hope this helps!
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(-3 - 5i )(-3 + 5i ) = -16 34 34 - 30
Virty [35]

You can use:

(a-b)(a+b)=a^2-b^2

We know:

i=\sqrt{-1}\to i^2=-1

Calculate:

(-3-5i)(-3+5i)=(-3)^2-(5i)^2=9-25i^2=9-25(-1)=9+25=34

6 0
3 years ago
3(-2-4v)&lt;-90 help I'm stuck on this one <br>​
Pavel [41]
Well, if you disregard the signs for a second, you can work this like a normal equation:
-6 - 12v = 90
-12v = 96
v = 8
Now just reincorporate the less than sign:
v < 8
5 0
3 years ago
HELP!!
Lorico [155]
C. Jasmine bought some tiles to put around her patio. . .

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6 0
3 years ago
Round 0.574 to the nearest tenth.
77julia77 [94]

Answer:

0.674

Step-by-step explanation:

5 0
3 years ago
Someone help me out on these 2 geometry questions, ASAP!!!<br> “Complete the proofs”
vodomira [7]

<u>Question 11</u>

1) \overline{BA} \cong \overline{FA}, \angle 1 \cong \angle 2 (given)

2) \angle A \cong \angle A (reflexive property)

3) \triangle AEB \cong \triangle ACF (ASA)

4) \overline{AC} \cong \overline{AE} (CPCTC)

<u>Question 12</u>

1) Isosceles \triangle ACD with \overline{AC} \cong \overline{AD}, \overline{BC} \cong \overline{ED} (given)

2) \angle ACD \cong \angle ADC (angles opposite congruent sides in a triangle are congruent)

3) \angle ACB and \angle ACD are supplementary. \angle ADC and \angle ADE are supplementary (angles that form a linear pair are supplementary)

4) \angle ACB \cong \angle ADE (supplements of congruent angles are congruent)

5) \triangle ABC \cong \triangle AED (SAS)

6) \overline{AB} \cong \overline{AE} (CPCTC)

7) \triangle ABE is an isosceles triangle (a triangle with two congruent sides is isosceles)

<em>Note: I changed the names of the segments in Question 11 because of the word filter.</em>

5 0
2 years ago
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