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weeeeeb [17]
4 years ago
6

Allen has four times as many cards as Bob, and Jane has twice as many cards as Allen. Together, Allen and Jane have 468 cards. H

ow many cards do Allen, Jane, and Bob each have?
Mathematics
1 answer:
fenix001 [56]4 years ago
5 0

Answer:

156

312 and

39

Step-by-step explanation:

Let Allen be A , Jane be J and Bob be B

Allen has 4 times as Bob

So

A = 4B

Jane has twice as Allen

So

J = 2A

Together, Allen and Jane has 468 cards

A + J = 468

Substitute 2A for J in the third equation.

We have

A + J = 468

A + 2A = 468

3A = 468

Divide both sides by 3

3A/3 = 468/3

A = 156

Recall

A = 4B

Therefore

156 = 4B

Divide both sides by 4

156/4 = 4B/4

39 = B

B = 39

Also,

J = 2A

J =2 x 156

J = 312

Allen has 156 cards

Jane has 312 cards and

Bob has 39 cards

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Solve 4\5x-4\10=2\20
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Jackie's restaurant bill was $23. 50, and the tax was 8%. Jackie left a 20% tip on the post-tax bill. How much was the tip Jacki
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well, the subtotal or pre-tax bill is $23.50, now let's add the 8% tax and

\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{8\% of 23.50}}{\left( \cfrac{8}{100} \right)23.50}\implies 1.88

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\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{20\% of 25.38}}{\left( \cfrac{20}{100} \right)25.38}\implies 5.076\qquad \approx 5.08

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Answer:

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