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8090 [49]
3 years ago
14

Find the center of the circle that can be circumscribed about EFG with E(4,4) F(4,2) G(8,2)

Mathematics
1 answer:
kipiarov [429]3 years ago
3 0

Answer:

The center of the circle is (6 , 3)

Step-by-step explanation:

∵ The vertices of Δ EFG are E (4 , 4) , F (4 , 2) , G (8 , 2)

∵ The x-coordinates of E and E are equal ∴ EF is vertical

∵ The y-coordinates of F and G are equal ∴ FG is horizontal

∴ m∠EFG = 90°

∵ The circle is circumscribed about Δ EFG

∴ E , F , G lie on the circle

∵ m∠F = 90°

∴ EG is the diameter of the circle

∴ The center of the circle is the mid-point of EG

∵ The mid-point of EG is (\frac{4+8}{2},\frac{4+2}{2})=(6,3)

∴ The center of the circle is (6 , 3)

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