Question

A spinner has red, green, blue, and orange sections. The probability of landing on red is 2/3, on green is 1/12, on blue is 1/12. In simplest form, what is the probability of landing on orange?

Answer 1

Answer:

Step-by-step explanation:

P(landing on orange)=1 - [2/3 + 1/12 + 1/12]

$=1-[\frac{2}{3}+\frac{2}{12}]\\\\=1-[\frac{2}{3}+\frac{1}{6}]\\\\=1-[\frac{2*2}{3*2}+\frac{1}{6}]\\\\=1-[\frac{4}{6}+\frac{1}{6}]\\\\=1-[\frac{4+1}{6}]\\\\=1-\frac{5}{6}\\\\=\frac{6}{6}-\frac{5}{6}\\\\=\frac{1}{6}$