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Sonbull [250]
4 years ago
8

Choices for Question #1:

Mathematics
1 answer:
hodyreva [135]4 years ago
7 0

Answer:

Question #1 choice A x=3, ST=24 and Question #2 choice C x =12

Step-by-step explanation:

Question #1

T midpoint so ST=TU and 8x = 2x+18

8x =2x+18

8x-2x=18

6x=18

x=18/6

x=3

so ST= 8x=8*3=24

choice A

Question #2

M midpoint of AB so AM=MB and 4x+1=7x-35

4x+1=7x-35

1+35=7x-4x

36=3x

36/3=x

12=x

choice C

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Step-by-step explanation:

The sine of an angle is equal to the cosine of its complement, so

4x+10=2x+16\\\\2x+10=16\\\\2x=6\\ \\ x=3

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15 POINTS ANSWER ASAP, SHOW WORK
forsale [732]

Answer:

V=97.6\ in^3

Step-by-step explanation:

step 1

Find the volume of the cylinder

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we have

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substitute

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step 2

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we have

we have

r=2\ in ---> the radius is the same that the radius of the cylinder

h=0.70\ in

substitute

V=\frac{1}{3}\pi (2)^{2} (0.70)\\\\V=0.93\pi\ in^3

step 3

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8 0
3 years ago
(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.
Andreyy89

\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1

Recall that

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

Your sums start at i=3, so in order to apply these formulas directly, you need to compensate for the missing first two terms:

\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8

\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52

\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}

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3 years ago
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