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sesenic [268]
3 years ago
11

What is the value of x and what’s the answer for b ?

Mathematics
1 answer:
Drupady [299]3 years ago
5 0
20^2 = 16^2 +x^2
400= 256+ x^2
x^2 = 400 -256
x = 144^1/2
=12

b. yes
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Three less than 11 times a number
Zarrin [17]

Answer: x = -1

Calculation/Explanation:

11x-3 = x-13

11x-3 -x = x-13 -x

10x-3 = -13

10x-3 +3 = -13 +3

10x = -10

10x /10 = -10/10

x = -1

4 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
Arada [10]

Given:

Scale factor s=\dfrac{1}{3}

Center of dilation = (4,2)

To find:

The coordinates of the points C' and A.

Solution:

We know that, if a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

The scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Suppose the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using rule (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Hence, the coordinates of Point C' are C'(2,5).

Let us assume that point A is A(m,n).

Using rule (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
Name four possible solutions to the inequality; X > -1
timama [110]
Really anything below -1
so the answer is -2 -3 -4 any of that
7 0
3 years ago
What inequality is shown by the graph?
Phantasy [73]

Answer:

the answer is A

Step-by-step explanation:

7 0
3 years ago
Find the coordinates for the midpoint of the segment with endpoints given. (12, 4) and (-8, 8) (2, 6) (10, 6) (2, 2)
cluponka [151]
The given coordinates are:
p1: (12,4) and p2: (-8,8)

Th x coordinate of the midpoint is calculated as follows:
Xmidpoint = (x1+x2) / 2 = (12+-8) / 2 = 4/2 = 2

The y coordinate of the midpoint is calculated as follows:
Ymidpoint = (y1+y2) / 2 = (4+8) / 2 = 12/2 = 6

Based on the above calculations, the midpoint of the segment with the given coordinates is (2,6)
8 0
3 years ago
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