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4 years ago

Plz plz plz I really need help

Mathematics

1 answer:

Naddik [55]4 years ago

6 0

The answer is:

23-5-c

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Is this statement true?

lara [203]

Answer:

yes and no,depends.

parrallel cant make any angles exept 180-straight line angle.

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3 years ago

8 X 9 X 2 = ? What is that?

svp [43]

Answer:

144

Step-by-step explanation:

8 x 9= 72

72 x 2= 144

8 0

3 years ago

Right triangle, slant side 20, short side 8, what is the other side?

choli [55]

It's also 8, a right triangle has two equal sides, and the slant.

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3 years ago

R= m/2 (c + K) for k

Wewaii [24]

Answer:

$\bold{K=\frac{2r}m-c=\frac{2r-cm}m}$

Step-by-step explanation:

$\bold{r= \frac m2 (c + K)}\\^{\div\frac m2}\qquad^{\div\frac m2}\\ \bold{r\cdot\frac2m=c+K}\\{}\ ^{-c}\qquad^{-c}\\\bold{\frac{2r}m-c=K}$

Or if you mean r= m/[2(c + K)]

$\bold{\quad r\ =\ \frac m{ 2(c + K)}}\\^{\cdot(c+K)}\quad^{\cdot(c+K)}\\ \bold{r(c+K)=\frac m2}\\{}\qquad ^{\div r}\qquad^{\div r}\\\bold{c+K=\frac m2\cdot\frac1r}\\{}\quad^{-c}\qquad^{-c}\\\bold{K=\frac m{2r}-c}$

5 0

3 years ago

Trigonometry . What

Kryger [21]

Answer:

Ques 11: 123.08 meters.

Ques 12: 269.4 meters.

Ques 13: 211.27 meters.

Step-by-step explanation:

Ques 11: We have that the angle of elevation from the ship to the top of the lighthouse is 18° and the height of the lighthouse is 40 m.

It is required to find the distance of the ship from the shore, say 'x' m.

As, we have, $\tan \theta=\frac{opposite}{adjacent}$

⇒ $\tan 18=\frac{40}{x}$

⇒ $x=\frac{40}{\tan 18}$

⇒ $x=\frac{40}{0.325}$

⇒ x = 123.08 m.

Thus, the distance of the ship from the shore is 123.08 meters.

Ques 12: We have, length of the kite is 300 m and the angle made by the string is 64°.

It is required to find the height of the kite, say 'x' m.

As, we have, $\sin\theta=\frac{opposite}{hypotenuse}$

⇒ $\sin 64=\frac{x}{300}$

⇒ $x=300\times \sin 64$

⇒ $x=300\times 0.898$

⇒ x = 269.4 m.

Hence, the height of the kite is 269.4 meters.

Ques 13: We have, the wreckage is found at the angle of 12° and the diver is lowered down by 45 meters.

It is required to find the distance covered by the diver to reach the wreckage, say 'x' m.

As, we have, $\tan \theta=\frac{opposite}{adjacent}$

⇒ $\tan 12=\frac{45}{x}$

⇒ $x=\frac{45}{\tan 12}$

⇒ $x=\frac{45}{0.213}$

⇒ x = 211.27 m.

Thus, the distance covered by the diver to reach the wreckage is 211.27 meters.

5 0

3 years ago