Answer:
K'= (-1,-1)
J'= (-1,-5)
L'= (0,-3)
Step-by-step explanation:
What you do here is, input the (x,y) coordinates into the translation.
For example, the original point K is (-3,5). Insert this into the translation.
(-3,5) → (-3+2, 5-8) = (-1,-3)
Repeat this for the next coordinates of L and J.
J= (-3,3)
(-3,3) → (-3+2, 3-8) = (-1,-5)
L= (-2, 5)
(-2, 5) → (-2+2, 5-8) = (0,-3)
Answer:
4.2 units
most likely answer choice B
Step-by-step explanation:
(1, 2) and (4, 5)
To find the distance between two points, we use the distance formula:

Let's plug in what we know.

Evaluate the parentheses.

Evaluate the exponents.

Add.

Evaluate the radical.
d = 4.24
Round to the nearest tenth.
d = 4.2 units
*note: The answer choice is 4.6. I'm not sure if that is a typo on someone's end, but the distance between these two points is exactly 4.24264068712 units.
Hope this helps!
Okay so you have to add up 15 and 11 and 4 so your answer is y=30
This ones kinda hard I'm not really sure, but looking at the table, when f(x) = 1, g(x) = 1. So therefore it is yes, and Im guessing you know the negative and positive x coordinates/zero thing, so I think you should be correct. Sorry if this is wrong, not too sure, but hopefully it gives you a better idea.