Answer:
Probability, P(getting 2 toppings)= 0.1984
Step-by-step explanation:
Probability, P(1 toppings)= 1/7
Probability P of getting a particular topping is q = 1 - P = 1 - 1/7 = 6/7
Probability of( getting 2 toppings)= 7!/(2!5!)(1/7)^2 × (6/7)^5
P(getting 2 toopings)= (5040/240) × (0.020)× (0.4627)
P(getting 2 toppings)= 21 × 0.00948 = 0.1984
b
152
3(11)= 33
4(33+5)
4(33)=132
4(5)=20
132+20=152
adding +2 on both sides to remove the -2 then it would be 2=0
I think 3
i think 3
for real this time
A
