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olga_2 [115]
3 years ago
15

You are ordering a hamburger and can get up to 7 toppings, but each topping can only be used once. You tell the cashier to surpr

ise you with the toppings you get. What is the probability that you get 2 toppings
Mathematics
1 answer:
natima [27]3 years ago
6 0

Answer:

Probability, P(getting 2 toppings)= 0.1984

Step-by-step explanation:

Probability, P(1 toppings)= 1/7

Probability P of getting a particular topping is q = 1 - P = 1 - 1/7 = 6/7

Probability of( getting 2 toppings)= 7!/(2!5!)(1/7)^2 × (6/7)^5

P(getting 2 toopings)= (5040/240) × (0.020)× (0.4627)

P(getting 2 toppings)= 21 × 0.00948 = 0.1984

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Jen spent $12 on school supplies. Percy spent 3 times as much on school supplies, and also bought a reusable water bottle for $6
Alex73 [517]

Answer:

12 * Answer:
12 x 3 = 36 + 6 = 42,
Step-by-step explanation:


Step-by-step explanation:

8 0
2 years ago
A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
Use the given values of n and p to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ. Round your answer to
fenix001 [56]

Given Information:  

number of trials = n = 1042

Probability of success = p = 0.80

Required Information:  

Maximum usual value = μ + 2σ = ?

Minimum usual value = μ - 2σ = ?

Answer:

Maximum usual value = 859.51

Minimum usual value = 807.78

Step-by-step explanation:

In a binomial distribution, the mean μ is given by

μ = np

μ = 1042*0.80

μ = 833.6

The standard deviation is given by

σ = √np(1 - p)

σ = √1042*0.80(1 - 0.80)

σ = √833.6(0.20)

σ = 12.91

The Maximum and Minimum usual values are

μ + 2σ = 833.6 + 2*12.91

μ + 2σ = 833.6 + 25.82

μ + 2σ = 859.51

μ - 2σ = 833.6 - 25.82

μ - 2σ = 807.78

Therefore, the minimum usual value is 807.78 and maximum usual value is 859.51

8 0
4 years ago
-3x - 7y=2<br> x + 3y = -2<br> solving systems by elimination
Andrew [12]

Answer:

(4,-2)

Step-by-step explanation:

x = 4

y = -2

5 0
3 years ago
Read 2 more answers
Decrease £220 by 15%
sasho [114]

220, percentage decreased by 15% (percent) of its value = 187
3 0
3 years ago
Read 2 more answers
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