Answer:
Number of students successful= 75
Number of students not able to complete the exam in the allotted time= 5
Step-by-step explanation:
In this question the main part is missing .The given statement is the sub part of the problem .
Suppose the main part is
<u><em>The time needed to complete a final examination in a particular college course is normally distributed with a mean of 80 minutes and a standard deviation of 10 minutes. </em></u>
<u><em></em></u>
If the main part was given like this only then we could do the following calculations.
So from above the
Population mean = μ= 80
Population Standard deviation =σ= 10 mins
Sample mean = x`= 95
Sample size= n= 80
Now first we calculate the z= score
z= x`-μ/σ
z= 95-80/10= 1.5
From the z- table we find the P (z< 1.5)= 0.9332
Now we have to find the number of students who need to complete the exam in the allotted time
Number of students successful= np= 80 * 0.9332= 74.656= 75
Number of students not able to complete the exam in the allotted time= 80-75= 5
<u><em>These answers are based on the main part supposed to be as added just to explain how it will be calculated.</em></u>
<u><em>There may be any discrepancy with the original question.</em></u>
Answer: ![2x^{2} y^{3} (\sqrt[3]{4x^{2} y} )](https://tex.z-dn.net/?f=2x%5E%7B2%7D%20y%5E%7B3%7D%20%28%5Csqrt%5B3%5D%7B4x%5E%7B2%7D%20y%7D%20%29)
Step-by-step explanation:
![\sqrt[3]{32x^{8} y^{10} } =\sqrt[3]{2^{3} \cdot 2^{2} \cdot x^{2} \cdot (x^{2} )^{3} \cdot y \cdot (y^{3})^{3} } =2x^{2} y^{3} (\sqrt[3]{4x^{2} y} )](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E%7B8%7D%20y%5E%7B10%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B2%5E%7B3%7D%20%5Ccdot%202%5E%7B2%7D%20%20%5Ccdot%20x%5E%7B2%7D%20%5Ccdot%20%28x%5E%7B2%7D%20%29%5E%7B3%7D%20%5Ccdot%20y%20%5Ccdot%20%28y%5E%7B3%7D%29%5E%7B3%7D%20%20%7D%20%3D2x%5E%7B2%7D%20y%5E%7B3%7D%20%28%5Csqrt%5B3%5D%7B4x%5E%7B2%7D%20y%7D%20%29)
Answer:
12 and -12
Step-by-step explanation:
12x-12y is the expansion using the distributive property, so the coefficient of x is 12 and the coefficient of y is -12
Answer:
Slope: 2; Y-Intercept: (0,3)
Step-by-step explanation:
As you can see from the graph, it rises 4 and runs 2. So, the slope is 2. It intersects the y axis at (0,3)
Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
