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VLD [36.1K]
3 years ago
7

What is .18 repeating as a fraction when the eight is only repeating?

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0
The answer to your question is 17/90:D
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Help, please! If possible explain it like your talking to a little kid :) Thank you♡
monitta

Answer:

GCF: y³z³

Step-by-step explanation:

The greatest common factor is the a term that you can take out of all the terms given to you. This term, when multiplied to each of the individual numbers in the set, will return you to the original amount.

In this case, note that they all share the variables y and z, and that each of them have <em>at least</em> 3 y's and 3 z's. For you to factor, you will divide these from all the terms.

\frac{x^{3}y^{5}z^{5} , y^{3}z^{5} , xy^{3}z^{3} }{y^{3}z^{3}} = x^{3}y^{2}z^{2} , z^{2} , x

y³z³(x³y²z² , z² , x)

~

7 0
3 years ago
. Use the vectors v = -i +2j and w= -3i + 4j to find 5v + 8w.
Anarel [89]
  • 5v+8w

put values

  • 5(-i+2j)+8(-3i+4j)

Do like you do algebraic addition

  • -5i+10j-24i+32j
  • -5i-24i+10j+32j
  • -29i+42j

Option A

5 0
2 years ago
A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measures 42,000 ft2. What is a dimension of the
dalvyx [7]

To solve the problem we must know about quadratic equations.

<h2>Quadratic Equation</h2>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

The breadth of the rectangle is 200 ft, while the length is 210 ft.

<h2>Explanation</h2>

Given to us

  • Area of the parking lot = 42,000 ft²
  • Perimeter of the parking lot = 820 ft

<h3>Area of the parking lot</h3>

Area of the parking lot = Area of the rectangle

42,000 ft² = Length x Breadth

Solving for L,

42,000 = L \times B\\\\&#10;L = \dfrac{42,000}{B}

<h3>Perimeter of the parking lot</h3>

Perimeter of the parking lot = Perimeter of the rectangle

820 ft. = 2(Length + Breadth)

820 ft. = 2(L+ B)

2(L+ B) = 820\\\\&#10;(L+B) = \dfrac{820}{2}\\\\&#10;(L+B) = 410

Substituting the value of L,

(L+B) = 410\\\\&#10;(\dfrac{42,000}{B}) +B = 410\\\\&#10;42000 + B^2 = 410B\\\\&#10;B^2 -410B +42000 = 0

<h3>Quadratic Expression</h3>

Solving the quadratic Expression,

B^2 -410B +42000 = 0\\\\&#10;(B-210)(B-200)=0

Equation the factors against zero,

B-210=0

B = 210

B-200=0

B = 200

Hence, the breadth of the rectangle is 200ft, while the length is 210 ft.

Learn more about Quadratic Expression:

brainly.com/question/10025464

4 0
3 years ago
Mathematical literacy​
melomori [17]

Answer:

hope that help

Step-by-step explanation:

Mathematical literacy is defined as: "an individual's capacity to formulate, employ and interpret mathematics in a variety of contexts. It includes reasoning mathematically and using mathematical concepts, procedures, facts and tools to describe, explain and predict phenomena.

4 0
3 years ago
If lim x-&gt; infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b
MAXImum [283]

We have

\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}

So

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0

The rational term vanishes as <em>x</em> gets arbitrarily large, so we can ignore that term, leaving us with

\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0

and this happens if <em>a</em> = 1 and <em>b</em> = -1.

To confirm, we have

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0

as required.

3 0
3 years ago
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