Answer:
51.63m^3
Step-by-step explanation:
The figure is made up of a rectangle, triangle and a semi circle
Area of the figure = Area of triangle + rectangle + semicircle
Area of the triangle = 1/2 * base * height
Area of the triangle = 1/2 * 3 * 5
Area of the triangle = 15/2
Area of the triangle = 7.5m^3
Area of the rectangle = Length * Width
Area of the rectangle = 6 * 5
Area of the rectangle = 30m^2
Area of the semicircle = πr²/2
Area of the semicircle = π(3)²/2
Area of the semicircle = 3.14(9)/2
Area of the semicircle = 3.14 * 4.5
Area of the semicircle = 14.13m^2
The area = 30 + 14.13+7.5
Area of the figure = 51.63m^3
Answer:
a. 5177 cm³
b. 3,451 cm³
c. 67%
Step-by-step explanation:
Given:
Diameter of each ball (d) = 13 cm
Radius of the ball (r) = radius of the cylinder = ½(13) = 6.5 cm
Height of the cylinder (h) = the sum of the diameters of the 3 balls = 3(13) = 39 cm
a. Volume of cylinder = πr²h
Plug in the values
Volume of cylinder = π*6.5²*39 = 5176.56 ≈ 5177 cm³
b. Total volume of the three balls = 3(volume of 1 ball) = 3(volume of sphere) = 3(⁴/3πr³)
Plug in the value
Total volume of the 3 balls = 3(⁴/3*π*6.5³) = 3(1150.35) = 3,451.05 ≈ 3,451 cm³
c. % of volume of the container occupied by the 3 balls = total volume of the three balls / volume of cylinder × 100
Plug in the values
= 3,451/5177 × 100
= 66.6602279
≈ 67%
Answer:
4
Step-by-step explanation:
one person is deemed to drive and that person is fixed on the driver's seat no mater which arrangement.
we have now 2 more seats one adjacent to the driver and one rear (two combined).
so the total ways in which all five can be arranged is as follows.
driver, adjacent to him(1) and three back.
driver adjacent to him (different person) and three back.
see the driver is always fixed so we can ignore him.
thus we when driver set fixed , on two remaining seats (adjacent to driver and the back )there can be 4 different combinations.
Answer:
270
Step-by-step explanation:
108 divided by 24 is 4.5. 4.5 is how many gallons per hour. then, 4.5 times 60 equals 270.
we are going to proceed as follows: 
equation (1)
equation (1)
in equation (2)
equation (3)
