Please help i will give out brainliest
1 answer:
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Step-by-step explanation:
Consider the provided information.
The total number of students are: 24+26+21=71
He wants each team will have the same number of students between 5 and 9.
The number between 5 to 9 are 6, 7 and 8.
The number 71 is a prime number so we need to divide the 71 students in group so that minimum students left without team.
Dividing 6 students in each group.
Number of teams: = 11 teams and 5 students.
Dividing 7 students in each group.
Number of teams: = 10 teams and 1 students.
Dividing 8 students in each group.
Number of teams: = 8 teams and 7 students.
Thus, we can not divide 71 students into equal teams, but 70 divided by 7 gives the least students left out i.e 10 teams each with 7 students and only 1 student will remain at last.
On top: (-2)³ = -2 × -2 × -2 = -8
(x²)³ = x^6 (the exponents multiply)
and of course, (y)³ = y³
On the bottom: (xy²z)² = x² y^4 z²
(-yz)² = y²z²
Multiplying these together, the exponents add and we get x² y^6 z^4.
So, your reasoning is correct for what you have so far.
Your next step would be cancelling shared factors from the top and bottom.
Just like with regular fractions, if the numerator and denominator are divisible by the same number, you can divide them by it to simplify. (ex: 4/6 = 2/3)
Well, x^6 and x^2 are both divisible by x^2, right?
We can also cancel the y^3.
It might help to visualise the factors like this:
Once you've cancelled out x² and y³ from each, you're left with