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Marina86 [1]
3 years ago
9

Help me out! I always mark brainliest. Unless of course, it is incorrect or inadequate. Please include how you did the problem.

Thanks!

Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0
If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
                        f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
                        f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
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Answer:

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Step-by-step explanation:

hope this helps

4 0
3 years ago
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erastova [34]

Answer:

Step-by-step explanation:

plug the numbers in and see if it is true

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is not true, so it is not a solution. even if it might be a solution for the other equation, it is not true for this equation so it is not a solution for this system

how to find an equation: since y=7x+8 and y=x+1, then

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6 0
3 years ago
Algebra question ( Matrices and Determinants ) 20 pints
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The correct answer is option D
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