Question

Twelve years ago my father was twice as old as I was, and three years ago our combined age was 138. How old (in years) is my father now?

Answer 1

Answer:

The present age of my Father is 92 years  .

Step-by-step explanation:

Given as :

Twelve years ago my father was twice as old as I was .

Three years ago our combined age was 138.

Now, From The statement

Let The age of my father = F

And The age of my = S

According to question

F - 12 = 2 × (S - 12)

Or, F - 12 = 2 S - 24

Or, 2 S - F = 24 - 12

∴ 2 S - F = 12                ..........1

Again

(F - 3) + (S - 3) = 138

Or, F + S - 6 = 138

Or, F + S = 138 + 6

∴  F + S = 144                 ...........2

Now, Solving equation 1 and 2

I.e (F + S) + (2 S - F) = 144 + 12

Or, (F - F) + (S + 2 S) = 156

Or, 0 + 3 S = 156

∴  S = $\frac{156}{3}$

I.e S = 52 years

So, The age of my = S = 52 years

Putting the value of S in Eq 2

I.e   F + S = 144  

or,  F + 52 = 144

Or, F = 144 - 52

∴    F = 92 years

So, The age of my father = F = 92 years

Hence The present age of my Father is 92 years  . Answer