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tangare [24]
3 years ago
6

How do i solve 2k^2-5k-18=0

Mathematics
1 answer:
devlian [24]3 years ago
5 0

Answer:

factor left the side of the equation

(2k_9)(k+2)=0

set factors equal to 0

2k_9=0 or k+2=0

the answer is K= 9/2 or K =-2

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Answer:

The Slope Intercept form of the equation through the point (0, -4) and

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Step-by-step explanation:

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Now, slope of the equation with points (a,b) and (c,d) is given as

m = \frac{d - b}{c -a}

So, here the slope of the line AB is given as:

m = \frac{0 - (-4)}{1-0} = \frac{4}{1}  = 4

⇒ m = 4

Now, by POINT SLOPE  form:

The equation with slope m and point  (x0 , y0) is represented as :

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⇒ The equation of AB is of the form with point (1,0) is

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Also, the SLOPE INTERCEPT form of an equation is of the form

y = m x + C ;     m = slope and C =  y -intercept

Hence, the slope intercept form of the equation through the point (0, -4) and (1, 0)  is  y = 4 x - 1

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