3 years ago

How do i solve 2k^2-5k-18=0

Mathematics

1 answer:

devlian [24]3 years ago

5 0

Answer:

factor left the side of the equation

(2k_9)(k+2)=0

set factors equal to 0

2k_9=0 or k+2=0

the answer is K= 9/2 or K =-2

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