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3 years ago

Can someone help me find the mean,median,mode

Mathematics

1 answer:

Yuri [45]3 years ago

7 0

Mean is the sum of the numbers divided by the number of number
41.42
The median is the middle number, in this case you add the two middle numbers and divide it by 2
61.615
the mode is the number that occurs the most
there is no mode

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Which expression is equivalent to RootIndex 3 StartRoot StartFraction 75 a Superscript 7 Baseline b Superscript 4 Baseline Over

slega [8]

Answer:

B. $\frac{b}{2a^{2}c^3}\sqrt[3]{15b}$

Step-by-step explanation:

Given:

The expression to simplify is given as:

$\sqrt[3]{\frac{75a^7b^4}{40a^{13}c^9}}$

Use the exponent property $\frac{a^m}{a^n}=a^{m-n}$

$\frac{a^7}{a^{13}}=a^{7-13}=a^{-6}$

Use the exponent property $(a^m)^n=a^{m\times n}$

$a^{-6}=a^{-2\times 3}=(a^{-2})^3$

$b^4=b\times b^3\\c^{9}=(c^3)^3$

Reducing $\frac{75}{40}$ to simplest form, we get:

$\frac{5\times 5\times 3}{2^3\times 5}=\frac{15}{2^3}$

Therefore, expression becomes:

$\sqrt[3]{\frac{15(a^{-2})^3\times b\times b^3}{2^3(c^3)^3}}$

Use the cubic root property:

$\sqrt[3]{x^3} =x$ . Thus, the expression becomes:

$\frac{a^{-2}b}{2c^3}\sqrt[3]{15b}$

Using the exponent property $a^{-m}=\frac{1}{a^m}$

$a^{-2}=\frac{1}{a^2}$

So, the final expression is:

$\frac{b}{2a^{2}c^3}\sqrt[3]{15b}$

Therefore, the correct option is option B.

7 0

4 years ago

What is the graph showing? I’m really confused.

Mamont248 [21]

Answer:

It is showing a slope of 1/4.

Step-by-step explanation:

It is also what a linear equation would look like on a graph.

6 0

3 years ago

Eight students were asked how many miles they live from school. Their answers are listed below.5, 4, 6, 1, 1, 1, 1, 4Find the mo

Tatiana [17]

Answers:
mode = 1
range = 5

-----------------------------------------

Explanation:

The mode is 1 because it is the most frequent value. It shows up four times compared to the other values (5,6) which only show up once and the value 4 only shows up twice.

The range is 5 because we subtract the max and min values to get 5.
In other words,
Range = Max - Min
Range = 6 - 1
Range = 5

7 0

3 years ago

4 measurements = 10 points Can anyone help?

m_a_m_a [10]

FIG A : ANGLE OF BAC = 67.38 °

FIG B : LENGTH OF RT = 10.549 cm

FIG C: LENGTH OF AB = 5.282 cm

FIG D: ANGLE OF ACB = 37.303°

Step-by-step explanation:

Fig A:

ABC angle = ( Opposite side) / (Hypotenuse)

Sin Ф = (12) / (13)

Ф = Sin⁻¹ ( 12/13)

Ф = 67.38 °

Fig B:

By the basic property of trigonometry

Tan Ф = (Opposite side) / (Adjacent side)

Tan Ф = (14)/ X

X= 14 / (Tan 53° )

Length of RT = 10.549 cm

Fig C:

By the basic property of trigonometry

Sin Ф = (Opposite side) / (Hypotenuse)

Sin Ф = (X) / 12.5

X = 12.5 $*$ Sin 25°

X= 5.282 cm

Fig D:

From the basic property of Trigonometry

Tan Ф = (Opposite side) / (Adjacent side)

Tan Ф = (8/10.5)

Ф = Tan⁻¹ ( 8/10.5)

Ф = 37.303°

8 0

4 years ago

Points -3,2 rotated 90 clockwise its a maze i need help o thank u

SCORPION-xisa [38]

Answer:

(2,3)

Step-by-step explanation:

Rotation through 90 clockwise gives the expression

( x , y )___ ( y ,- x )

so when you put the points -3 ,2 in the relation , it becomes

( -3 , 2 ) ___ ( 2, - -3 )

= ( x, y ) __ ( 2, 3 ). meaning when you rotate -3,2 through 90 clockwise you will get the image ( 2 ,3 )

6 0

4 years ago