Question

Solve the triangle, please help

Answer 1

Answer:

Side A = 14; Side B = 24.25; Side C = 28 |

Angle A = 60 degrees; Angle B = 30 degrees; Angle C = 90 degrees

Step-by-step explanation:

Okay, I find this question a bit weird because you already have two sides

So, I'm going to assume:

Side A = 14

Side B = 24.25

Finding side C

Using Pythagoras theorem

$a^2 + b^2 = c^2$

$14^2 + 24.25^2 = c^2$

$196 + 588.0625 = c^2$

$c=\sqrt{784.0625}$

c = 28 units (28.00111605)

Finding Angles (A,B and C)

In the diagram, we can see there is a right angle triangle, and a little square

Therefore, we can say that Angle C is 90 degrees

Finding Angle A/B:

There are so many ways to find it, I'll just use this though

Method: Using SOHCAHTOA to find B, then finding A

Using SOHCAHTOA

I'll be using the sine rule to find Angle B

$sin =\frac{opposite}{hypotenuse}$

$sin^-1 (\frac{14}{28} )$

Angle B = 30 degrees

The interior angles in a triangle add up to 180 degrees

Angle A = 180 - (90 + 30)

Angle A = 60 degrees

Verify:

60 + 30 + 90 = 180