ANOTHER DIFFICULT ONE!...for me..
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they must have 1.33 teaspoons of medication for child weighing 40 pounds !
<u>Step-by-step explanation:</u>
Here we have , Your child needs a fever medication at 3:00 in the morning. The package says to give two teaspoons to a sixty-pound child. If your child weighs forty pounds, We need to find how much should they have. Let's find out :
For medication purpose , 60 pounds require 2 teaspoons . So , 1 pounds require :
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So , for 40 pounds we require number of teaspoons as :
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Therefore , they must have 1.33 teaspoons of medication for child weighing 40 pounds !
Answer:
For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5
For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5
No, the box plots are not symmetric.
Step-by-step explanation:
Part A
The given data sets are
School A : 9,14,15,17,17,7,15,6,6
School B : 12,8,13,11,19,15,16,5,8
Arrange the data in ascending order.
School A : 6,6,7,9,14,15,15,17,17
School B : 5,8,8,11,12,13,15,16,19
Divide each data set in four equal parts.
School A : (6,6),(7,9),14,(15,15),(17,17)
School B : (5,8),(8,11),12,(13,15),(16,19)
For school A:
Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17
Interquartile range of the data is
For school B:
Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19
Interquartile range of the data is
Part B:
The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.