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3 years ago

Answer key please I don’t know what to do cause i missed the days

Mathematics

1 answer:

Makovka662 [10]3 years ago

4 0

Answer:

L 41/3 14 [200] G

Step-by-step explanation:

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A bag contains 30 red and blue marbles. If 19 are blue, what fraction of the marbles are blue?

Musya8 [376]

Answer:

19%

Step-by-step explanation:

19/100. i don't think it is that simple, but i did the best i could

5 0

3 years ago

Please help me please

VLD [36.1K]

Answer:

A for the second part

2/1

Step-by-step explanation:

an inequality is a comparison.

3 0

3 years ago

Sequences.

natta225 [31]

Answer:

192.

Step-by-step explanation:

The formula you can write is y=6x, with x being the sequence number and y being the value of that number. Plugging in 32, the 32nd number would be 192.

8 0

3 years ago

Hong reads 9 3/4 chapters in 3 3/8 hours. What is the unit rate in chapters per hour? Write your answer as a fraction or a mixed

Sav [38]

The unit rate is: $2\frac{8}{9}$ chapters per hour

Step-by-step explanation:

Given

chapters read = $9\frac{3}{4} = \frac{39}{4}$

Time = $3\frac{3}{8} = \frac{27}{8}$

Unit rate is calculated by dividing the total chapters by total time

So,

$Unit\ rate = \frac{\frac{39}{4}}{\frac{27}{8}}\\= \frac{39}{4} * \frac{8}{27}\\= 13 * \frac{2}{9}\\=\frac{26}{9}\\=2\frac{8}{9}$

Hence,

The unit rate is: $2\frac{8}{9}$ chapters per hour

Keywords: Unit rate, fractions

Learn more about fractions at:

#LearnwithBrainly

4 0

4 years ago

Find the exact value of tan(165°) using a difference of two angles

Katyanochek1 [597]

Answer: $-2+\sqrt{3}$

=========================================================

Work Shown:

Apply the following trig identity

$\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\$

Now let's rationalize the denominator

$\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\$

----------------------

As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.

Or you can note how

$\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949$

which helps us see that they are the same thing.

Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as $\sqrt{3}-2$ but it's the same as above.

5 0

3 years ago