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GaryK [48]
3 years ago
6

3 integers less than 25 range of 10 mean of 13​

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

8, 13, 18

Step-by-step explanation:

If we want the mean to be 13, and there are 3 integers, that means the sum of all 3 integers must be 39. I started at 13 and counted 5 up and 5 down, which already makes sure of the range and the mean is 13 (since it's balanced with 13 being the middle), therefore, 13+5 is 18, 13-5=8.

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Which equation in rectangular form describes the parametric equations x=5-3cost and y=4+2sint?
Sidana [21]

Answer:

D. (-x+5)^2/9+(y-4)^2/4=1    (I assume there was a mistype)

Step-by-step explanation:

The first step is isolating the sine and cosine functions.

x=5-3cos(t)

x + 3cos(t) = 5

3cos(t) = 5 - x

cos(t) = (5 - x)/3

y=4+2sin(t)

y - 4 = 2sin(t)

(y - 4)/2 = sin(t)

Then, square at both sides of the equal sign

cos²(t) = (5 - x)²/3² = (5 - x)²/9

sin²(t) = (y - 4)²/2² = (y - 4)²/4

Recall the trigonometric identity and replace.

cos²(t) + sin²(t) = 1

(5 - x)²/9 + (y - 4)²/4 = 1

8 0
3 years ago
A fair coin is flipped 120 times. Estimate the expected number of ‘heads’.
Bumek [7]

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n=10

so

mean = E[x] = np =10*0.5 =5

7 0
2 years ago
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The the seats in the van are in pairs there are 16 seats How many pairs of seats are there
miskamm [114]
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4 0
3 years ago
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between 1995 and 2006, the population of samburg, usa(in thousands) can be modeled by f(x) = 0.35x(squared) - 2.1x+15.8 where x=
Juli2301 [7.4K]
\bf f(x)=0.35x^2-2.1x+15.8\qquad 
\begin{cases}
x=\textit{year since 1995}\\
f(x)=\textit{population amount}
\end{cases}

the equation is a quadratic one, and it has a positive coefficient on the leading term, meaning, is opening upwards, so it has a "burrow" for the vertex.

the minimum or lowest point for a quadratic opening upwards is, well, the vertex point :),   the "x" value is the year, the "y" or f(x) value is the population, we're asked for the year, or the x-coordinate of the vertex

well   \bf \begin{array}{llll}
f(x)=&0.35x^2&-2.1x&+15.8\\
&\quad \uparrow &\quad \uparrow&\uparrow \\
&\quad  a&\quad  b &c
\end{array}
\\\\

\\\\
\qquad  \textit{vertex of a parabola}\\ \quad \\
\qquad 

\left(\boxed{-\cfrac{{{ b}}}{2{{ a}}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
5 0
3 years ago
Range, mode, MAD, median IQR, mean
Jlenok [28]

Answer:

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Step-by-step explanation:

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mode= most frequent

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6 0
3 years ago
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