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GaryK [48]
3 years ago
6

3 integers less than 25 range of 10 mean of 13​

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

8, 13, 18

Step-by-step explanation:

If we want the mean to be 13, and there are 3 integers, that means the sum of all 3 integers must be 39. I started at 13 and counted 5 up and 5 down, which already makes sure of the range and the mean is 13 (since it's balanced with 13 being the middle), therefore, 13+5 is 18, 13-5=8.

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Caroline's hair is
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The inequality can be used to determine how many months will it take for Caroline's hair to be at least as long as Trinity's hair is (1/5)x + 7 ≥ (1/10)x + 10

<h3>What is an equation? </h3>

An equation is an expression that shows the relationship between two or more numbers and variables. An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.

Let x represent the number of months.

For Caroline's hair:

Length = (1/5)x + 7

For Trinity's hair:

Length = (1/10)x + 10

For Caroline's hair to be at least as long as Trinity's hair, hence:

(1/5)x + 7 ≥ (1/10)x + 10

The inequality can be used to determine how many months will it take for Caroline's hair to be at least as long as Trinity's hair is (1/5)x + 7 ≥ (1/10)x + 10

Find out more on equation at: brainly.com/question/2972832

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At basketball practice, charlie makes 52 baskets out of 80 shots. What percentage of baskets did he make?
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Given that f(x) = 19x2 + 152, solve the equation f(x) = 0
telo118 [61]

<em><u>Option A</u></em>

<em><u>The solution is:</u></em>

x = \pm 2i \sqrt{2}

<em><u>Solution:</u></em>

f(x) = 19x^2+152

We have to solve the equation f(x) = 0

Let f(x) = 0

0=19x^2+152

Solve the above equation

19x^2 + 152 = 0

\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8

Take square root on both sides

x =  \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}

Thus the solution is found

5 0
3 years ago
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