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abruzzese [7]
3 years ago
15

1-5 or as many as you can please

Mathematics
1 answer:
Stels [109]3 years ago
7 0

Answer:

1) (3c + 1 )(3c + 2)

2) 8x^2 + 26x  - 7

3) 6

4) 16x^2 - 48xy^3 + 36y^6

5) (5x - 2y)(2x - 5y)


Step-by-step explanation:

1) 9c^2 + 9c + 2 = (3c + 1 )(3c + 2)

2) (4x - 1)(2x + 7)

= 8x^2 + 28x - 2x - 7

= 8x^2 + 26x  - 7

3) 7m^6n^5

Highest degree is 6 (m^6)

answer: 6

4)

(4x - 6y^3)^2

= (4x)^2 - 2(4x)(6y^3) + (6y^3)^2

= 16x^2 - 48xy^3 + 36y^6

5)

10x^2 - 29xy + 10y^2

= (5x - 2y)(2x - 5y)

because if if distribute (5x - 2y)(2x - 5y)

= 10x^2 - 25xy - 4xy + 10y^2

= 10x^2 - 29xy + 10y^2

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3 0
3 years ago
Read 2 more answers
X ^ 2 + 4x - 7 = 0<br><br> Solve using the Quadratic Formula
aalyn [17]

There's a special case of the quadratic formula called the Shakespeare Quadratic Formula (2b or -2b) that applies when the linear coefficient is even.

x^2-2Bx + C \textrm{ has zeros }x = B \pm\sqrt{B^2 - C}

If you're planning on solving a lot of quadratic equations quickly, it's good to know.

Here we have

x^2 + 4x - 7 = 0

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x = -2 \pm \sqrt{2^2 - -7}

x = -2 \pm \sqrt{11}

8 0
3 years ago
Solve the following system of equations:
PSYCHO15rus [73]
If we multiply the first equation by 2 we get
2x - 4y = 12
but the second equation is
2x - 4y = 10

2x - 4y can't have 2 different values  so the are no solutions 
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3 years ago
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find the value of the polygon. the polygon has 6 interior angles 2 of them are y and 4 of them are (2Y-20)
Anna35 [415]
First we need to determine what the 6 angles must add to. Turns out we use this formula

S = 180(n-2)

where S is the sum of the angles (result of adding them all up) and n is the number of sides. In this case, n = 6. So let's plug that in to get

S = 180(n-2)
S = 180(6-2)
S = 180(4)
S = 720

The six angles, whatever they are individually, add to 720 degrees. The six angles are y, y, 2y-20, 2y-20,  2y-20,  2y-20, <span> 

They add up and must be equal to 720, so let's set up the equation to get...

(y)+(y)+(</span>2y-20)+(2y-20)+(2y-20)+(<span>2y-20) = 720

Let's solve for y

</span>y+y+2y-20+2y-20+2y-20+2y-20 = 720

10y-80 = 720

10y-80+80 = 720+80

<span>10y = 800
</span>
10y/10 = 800/10

y = 80

Now that we know the value of y, we can figure out the six angles

angle1 = y = 80 degrees
<span>angle2 = y = 80 degrees
</span><span>angle3 = 2y-20 = 2*80-20 = 140 degrees
</span>angle4 = 2y-20 = 2*80-20 =<span> 140 degrees
</span><span>angle5 = 2y-20 = 2*80-20 = 140 degrees
</span>angle6 = 2y-20 = 2*80-20 =<span> 140 degrees
</span>
and that's all there is to it
3 0
3 years ago
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