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3 years ago

I need help asap pls

Mathematics

2 answers:

Tema [17]3 years ago

5 0

If Michael is bike riding at a speed of 4 miles an hour you would multiply 4 miles by the hour

So it would be x times y
0x4=0
1x4=4
2x4=8
3x4=12
4x4=16
5x4=20
9x4=36
1/2x4=2

Arisa [49]3 years ago

5 0

Miles travelled = 4 x hours

Constant of proportionality: y = 4x

1 hour = 4 miles

2 hours = 8 miles

3 hours = 12 miles. 4 hours = 16 miles. 5 hours = 20 miles. 9 hours = 36 miles.

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In a standard 52-card deck, half of the cards are red and half are black. The 52 cards are divided evenly into 4 suits: spades,

liubo4ka [24]

Answer:

It is more likely she draws 2 red cards

Step-by-step explanation:

Given that:

Number of red d cards in deck = 26

Number of face cards = 4 * 3 = 12 face cards

If two cards are drawn with replacement ;

Probability = (required outcome / Total possible outcomes)

P(1st card red) = 26 /52) = 1/2

P(2nd card red) = 26 /52 = 1/2

P(1st card red) * P(2nd card red)

1/2 * 1/2 = 1/4 = 0.25

P(1st card face card) = 12/52 = 3/13

P(2nd card, face card) = 12/52 = 3/13

P(1st card face card) * P(2nd card face card)

3/13 * 3 /13 = 9/169 = 0.053

0.25 > 0.053

It is more likely she draws 2 red cards

6 0

3 years ago

Julio bought several books from the Coming-Around-Again Bookstore. He paid $31.80, including 6% sales tax. He then discovered th

ladessa [460]

C is the answer all you had to do was
31.80-4.00
Which is 27.80
Then add 2.50
Which is 30.3!

5 0

3 years ago

Show why the limit as x approaches 0 (csc(x)-cot(x)) involves an indeterminate form, and then prove that the limit equals 0.

Nadusha1986 [10]

Answer with Step-by-step explanation:

We are given that $\lim_{x\rightarrow 0 }(csc(x)-cot(x))$

We have to prove that why the limit x approaches 0(csc(x)-cot(x)) involves an indeterminate form and prove that the limit equals to 0.

$\lim_{x\rightarrow 0 }(\frac{1}{sinx}-\frac{cosx}{sinx})$

Because $csc(x)=\frac{1}{sinx}$ and $cot(x)=\frac{cosx}{sinx}$

$\lim_{x\rightarrow 0 }(\frac{1-cosx}{sinx})$

$\frac{1-cos0}{sin0}$

We know that cos 0=1 and sin 0=0

Substitute the values then we get

$\frac{1-1}{0}=\frac{0}{0}$

We know that $\frac{0}{0}$ is indeterminate form

Hence, the limit x approaches 0(csc(x)-cot(x)) involves an indeterminate form.

L'hospital rule:Apply this rule and differentiate numerator and denominator separately when after applying $\lim_{x\rightarrow a }$ we get indeterminate form $\frac{0}{0}$