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Irina18 [472]
3 years ago
9

Which value for x makes the sentence true?

Mathematics
2 answers:
Kipish [7]3 years ago
8 0
I hope this helps you out

Vladimir [108]3 years ago
3 0
The answer is 5,x =5
5 (9x-6)+15=210
5×9×5=225
5×6=30
225-30=195
195+15=210
see,simple enough to understand
And it is explained step by step
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https://lh5.googleusercontent.com/BTB8IVPp1M9ftWYrmUv4V29JTOIu-fUaQRDbERGKuRvHwen-iiK29m3v1rhGvp6kX40Rv0TBORmiPdtdKLoAv9vuG5Hp5Z
marshall27 [118]

Answer:

it won't let me see the link

8 0
3 years ago
Read 2 more answers
37% of what number is 72?
tatiyna
The answer is 194.59

(72 x 100) / 37 = 194.59
4 0
2 years ago
Read 2 more answers
Find the negation of the proposition
murzikaleks [220]

In accordance with <em>propositional</em> logic, <em>quantifier</em> theory and definitions of <em>simple</em> and <em>composite</em> propositions, the negation of a implication has the following equivalence:

\neg (\exists \,x\, (P(x) \implies  Q(x))) \iff \forall \,x (\neg \,Q(x) \,\land \,P(x)) (Correct choice: iii)

<h3>How to find the equivalent form of a proposition</h3>

Herein we have a <em>composite</em> proposition, that is, the union of <em>monary</em> and <em>binary</em> operators and <em>simple</em> propositions. According to <em>propositional</em> logic and <em>quantifier</em> theory, the negation of an implication is equivalent to:

\neg (\exists \,x\, (P(x) \implies  Q(x))) \iff \forall \,x (\neg \,Q(x) \,\land \,P(x))

To learn more on propositions: brainly.com/question/14789062

#SPJ1

8 0
2 years ago
All ir rational numbers are rational numbers
patriot [66]

Answer:

no

Step-by-step explanation:

false

irrational numbers cannot be rational

8 0
3 years ago
Graph the system of inequalities to show all possible solutions.<br> {y&lt;3x-2<br> {y ≥ -x+3
Semmy [17]

Answer:

see attachment for graph

Step-by-step explanation:

< or > : dashed line

≤ or ≥ : solid line

< or ≤ : shade below the line

> or ≥ : shade above the line

<u>To graph the line y < 3x-2</u>

Rewrite the equation as: y = 3x - 2

Find two points on the line:

when x = 0,  y = 3(0) - 2 = -2  →  (0, -2)

when x = 3,  y = 3(3) - 2 = 7  →  (3, 7)

Plots the found points (0, -2) and (3, 7).

Draw a straight, dashed line through the points.

<u>To graph the line y ≥ -x + 3</u>

Rewrite the equation as: y = -x + 3

Find two points on the line:

when x = 0,  y = -(0) + 3 = 3  →  (0, 3)

when x = 3,  y = -(3) + 3 = 0  →  (3, 0)

Plots the found points (0, 3) and (3, 0).

Draw a straight, solid line through the points.

Shade above the solid line and below the dashed line to the right of where the two lines intersect.  <u>The shaded area is the area of all possible solutions</u>.

5 0
2 years ago
Read 2 more answers
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