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3 years ago

PLZ HELP ASAP WILL MARK BRAINLIEST

Mathematics

1 answer:

Mkey [24]3 years ago

3 0

DEF will be 2.68

EF will be .67

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Javier's parents set an amount of money aside when he was born. They earned 4.5% simple interest on that money each year. When J

solmaris [256]

Answer:

Javier's parents set aside $1500 when he was born

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

In this question, we have that:

$E = 1012.50, t = 15, I = 0.045$

We have to find P. So

$E = P*I*t$

$1012.50 = P*15*0.045$

$P = \frac{1012.50}{15*0.045}$

$P = 1500$

Javier's parents set aside $1500 when he was born

6 0

2 years ago

-48=-8x+8 solve the equation

aleksley [76]

Answer:

x=7

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the value of f(x) = 9x when x = -2? A. 1 81 B. 81 C. 1 18 D. 18

egoroff_w [7]

Answer:

Step-by-step explanation:

The correct answer would be -18

To solve this, you would substitute x with the x value, which in this case is -2

That would make it so f(x)= 9(-2)

9*-2=-18

Therefore f(x)=-18

3 0

3 years ago

Read 2 more answers

Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

Leya [2.2K]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6$

6 0

3 years ago

Brad needs to rent scaffolding to paint a 2-story room. Handy Rentals charges $15 plus $12.50 per hour. The EZ Rental Company ch

mrs_skeptik [129]

Answer:

6 hours

Step-by-step explanation:

lmk if you want an explanation

6 0

2 years ago