Simplify: 10√11(4√6+7) HELPPPP

Lesechka [4]

Step-by-step explanation:

Hi there!!! 

The answer is option A. 

reason look in picture. 

if you want to solve it just cross multiply it,

 $60x = 240000 \times 100$ 

or,

 $x = 24000000 \div 60$ 

and the answer would be 400000.

Hope it helps...

5 0

3 years ago

Kara mixes different colors of paint to create new colors. The table shows the amount of paint Kara mixes per batch.

Sergio [31]

Answer:

D. Batch 5.

Step-by-step explanation:

The batch should have the same proportion of blue to white to yellow.

In Batch 1, there are two parts of blue, 1.5 parts of white, and 1 part of yellow.

In Batch 5, there are four parts of blue, 3 parts of white, and 2 parts of yellow.

4 / 2 = 2

3 / 2 = 1.5

2 / 2 = 1

Since the proportions are equal to those found in Batch 1, D. Batch 5 will create the same colors as the first batch.

Hope this helps!

8 0

3 years ago

Greenville and north valley are 4.5 inches apart 1 inch equals 20 mkiles

Greeley [361]

90 would be your answer.

5 0

3 years ago

Need help with these math questions please.

Bas_tet [7]

Answer:

8 - 2π square units.

π/16 - 1/8 square units.

6π - 9√3 square units.

Step-by-step explanation:

The area of the square = 2√2 * 2√2

= 2*2*2

= 8.

The area of the circle = πr^2

= π * [ ( 2√2)/ 2) ]^2

= π (√2)^2

= 2π.

Second Question:

The area of the circle = π(1/2)^2 = π/4.

Finding the area of the square:

1^2 = 2x^2

x^2 = 1/2

So the area of the square = 1/2

So the area of the red part = 1/4 ( π/4 - 1/2).

= π/16 - 1/8.

Third question

Area of the circle = 6^2 * π = 36π.

Now 60 degrees is 1/6 of 360 degrees so the are of the sector is 6π.

The area of the segment = 6π - 0.5 * 6^2 sin 60

= 6π - 18√3/2

= 6π - 9√3 square units.

6 0

2 years ago

A given population proportion is .25. What is the probability of getting each of the following sample proportions

anyanavicka [17]

This question is incomplete, the complete question is;

A given population proportion is .25. What is the probability of getting each of the following sample proportions

a) n = 110 and = p^ ≤ 0.21, prob = ?

b) n = 33 and p^ > 0.24, prob = ?

Round all z values to 2 decimal places. Round all intermediate calculation and answers to 4 decimal places.)

Answer:

a) the probability of getting the sample proportion is 0.1660

b) the probability of getting the sample proportion is 0.5517

Step-by-step explanation:

Given the data in the questions

a)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 110

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 110 ) √( 0.1875 / 110 ) = 0.0413

Now, P( p^ ≤ 0.21 )

= P[ (( p^ - μ ) /S.D) < (( 0.21 - μ ) / S.D)

= P[ Z < ( 0.21 - 0.25 ) / 0.0413)

= P[ Z < -0.04 / 0.0413]

= P[ Z < -0.97 ]

from z-score table

P( X ≤ 0.21 ) = 0.1660

Therefore, the probability of getting the sample proportion is 0.1660

b)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 33

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 33 ) = √( 0.1875 / 33 ) = 0.0754

Now, P( p^ > 0.24 )

= P[ (( p^ - μ ) /S.D) > (( 0.24 - μ ) / S.D)

= P[ Z > ( 0.24 - 0.25 ) / 0.0754 )

= P[ Z > -0.01 / 0.0754 ]

= P[ Z > -0.13 ]

= 1 - P[ Z < -0.13 ]

from z-score table

{P[ Z < -0.13 ] = 0.4483}

1 - 0.4483

P( p^ > 0.24 ) = 0.5517

Therefore, the probability of getting the sample proportion is 0.5517

6 0

2 years ago