All categories

2 years ago

What is g’(x)? Calculus derivative help

Mathematics

1 answer:

Dominik [7]2 years ago

7 0

Answer:

Step-by-step explanation:

h'(x) = [f(x)*g(x)] '=f'(x )g(x) + f(x)g'(x)

h'(1) = [f(1)*g(1)] '=f '(1)g(1) + f(1)g'(1)

From the table f '(1)= -3, g(1)=2, f(1)= 3, g'(1) =6

h'(1) = f '(1)g(1) + f(1)g'(1) = -3*2 + 3*6= - 6+ 18 = 12

You might be interested in

Create diagrams to represent the possible cases for common tangents between two circles. Your diagram can be created using multi

Anastaziya [24]

I made mine from google drawings

3 0

3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

8 months ago

Using a graphical method, solve the simultaneous equations x+y =4 and y=2x+1

adoni [48]

Answer:

(1, 3)

Step-by-step explanation:

Given the expression

x+y = 4 ... 1

y = 2x+1 ....2

Substitute equation 2 into 1

x + (2x+1) = 4

3x + 1 = 4

3x = 4-1

x = 3/3

x = 1

Since y = 2x + 1

y = 2(1) + 1

y = 3

Hence the solution to the equation is (1,3). This means that the coordinate point on the graph where both lines intersect will be at (1, 3)

7 0

2 years ago

Need to find volume, step by step explanation pls

worty [1.4K]

Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

$V_1=\dfrac{2}{3}\pi r^3$

Where, r is the radius of the hemisphere.

$V_1=\dfrac{2}{3}(3.14)(6)^3$

$V_1=\dfrac{6.28}{3}(216)$

$V_1=452.16$

Volume of cylinder is:

$V_2=\pi r^2h$

Where, r is the radius of the cylinder and h is the height of the cylinder.

$V_2=(3.14)(6)^2(12)$

$V_2=(3.14)(36)(12)$

$V_2=1356.48$

We know that,

$l^2=r^2+h^2$ [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

$(10)^2=(6)^2+h^2$

$100-36=h^2$

$\sqrt{64}=h$

$8=h$

Volume of cone is:

$V_3=\dfrac{1}{3}\pi r^2h$

Where, r is the radius of the cone and h is the height of the cone.

$V_3=\dfrac{1}{3}(3.14)(6)^2(8)$

$V_3=\dfrac{25.12}{3}(36)$

$V_3=301.44$

Now, the volume of the combined figure is:

$V=V_1+V_2+V_3$

$V=452.16+1356.48+301.44$

$V=2110.08$

Therefore, the volume of the given figure is 2110.08 cubic units.

7 0

2 years ago

ASAP please help!!!

Serggg [28]

Y+4<9
subtract 4
y<5
y is smaller than and equal to 5
so you shade from 5 to the negative end to infinity (to the left) and shade the 5 to show that it is included (attachment says A)

6 less than (-6) 2 times a number (2 time x) is greater than (>) 8 (8)

-6+2x>8
add 6
2x>14
divide 2
x>7
so
x is bigger than 7
shade from 7 to the positive end to infinity (to the right) and don't shade 7 but put a circle around it to show that it is not included (attachment says B )

I have included pictures of the number lines

4 0

3 years ago