Without considering the sign:
It's sigma(1 to 5, 5k+2)
Since the first item is minus, you simply add (-1)^k
So it's sigma(1 to 5, (-1)^k * (5k+2)
I choose A
Answer:
percentage change from 1960 to 1970 =( 0.11 ÷0.25 ) × 100
= 44 %
Percentage change from 1970 to 1980 =( 0.83 ÷ 0.36) × 100
= 230.55%
percentage change from 1980 to 1990 = ( 0.16 ÷ 1.19) × 100
= 13.44%
percentage change from 1990 to 2000 = (- 0.09 ÷ 1.35) × 100
= -6.667%
Step-by-step explanation:
Item : 1960 1970 1980 1990 2000
gallon: $0.25 $0.36 $1.19 $1.35 $1.26
change : 0.36 - 0.25 = 0.11
percentage change from 1960 to 1970 =( 0.11 ÷0.25 ) × 100
= 44 %
Percentage change from 1970 to 1980 =( 0.83 ÷ 0.36) × 100
= 230.55%
percentage change from 1980 to 1990 = ( 0.16 ÷ 1.19) × 100
= 13.44%
percentage change from 1990 to 2000 = (- 0.09 ÷ 1.35) × 100
= -6.667%
Answer:
-864
Step-by-step explanation:
The determinant of a matrix product is the product of the determinants. The determinant of a transpose is the same as the determinant of the original. Hence ...

The multiplication of an n×n matrix by a scalar 'a' multiplies its determinant by a^n, so the desired determinant is ...

Infinitely many solutions means that you have the same thing on both sides of the equation no matter what value of x you plug in, right?
We just need both sides to be 3x then, correct?
If a were equal to 3 and b were equal to 0, we'd have
3x = (3)x + 0
Which is essentially 3x = 3x
So that means a = 3 and b = 0 must work!
Let's say x = 5
3(5) = 3(5) + 0
15 = 15 + 0
15 = 15
That means that a = 3 and b = 0 is your final answer :)