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ddd [48]
3 years ago
11

Solve the right triangle, ΔABC, for the missing sides and angle to the nearest tenth given angle B = 27° and side c = 15.

Mathematics
1 answer:
nignag [31]3 years ago
6 0

Answer:

Part 1) C=90\°

Part 2) A=63\°

Part 3) b=6.8\ units

Part 4) a=13.4\ units

Step-by-step explanation:

step 1

Find the measure of angle C

we know that

The triangle ABC is a right triangle

so

Angle C is a right angle

therefore

C=90\°

step 2

Fin the measure of angle A

we know that

In the right triangle ABC

∠B+∠A=90° -----> by complementary angles

we have

B=27\°

substitute

27\°+A=90\°

A=63\°

step 3

Find the length side b

we know that

In the right triangle ABC

sin(B)=b/c

b=(c)sin(B)

substitute the given values

b=(15)sin(27\°)=6.8\ units

step 4

Find the length side a

we know that

In the right triangle ABC

sin(A)=a/c

a=(c)sin(A)

substitute the given values

a=(15)sin(63\°)=13.4\ units

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A certain standardized test's math scores have a bell-shaped distribution with a mean of 525 and a standard deviation of 119. Co
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Using the normal distribution, it is found that:

a) 68.2% of standardized test scores are between 406 and 644.

b) 31.8% of standardized test scores are less than 406 or greater than 644.

c) 2.3% of standardized test scores are greater than 763.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 525, hence \mu = 525.
  • The standard deviation is of 119, hence \sigma = 119.

Item a:

The proportion is the <u>p-value of Z when X = 644 subtracted by the p-value of Z when X = 406</u>, hence:

X = 644:

Z = \frac{X - \mu}{\sigma}

Z = \frac{644 - 525}{119}

Z = 1

Z = 1 has a p-value of 0.841.

X = 406:

Z = \frac{X - \mu}{\sigma}

Z = \frac{406 - 525}{119}

Z = -1

Z = -1 has a p-value of 0.159.

0.841 - 0.159 = 0.682.

0.682 = 68.2% of standardized test scores are between 406 and 644.

Item b:

Complementary event to the one found in item A, hence:

1 - 0.682 = 0.318.

0.318 = 31.8% of standardized test scores are less than 406 or greater than 644.

Item c:

The proportion is <u>1 subtracted by the p-value of Z when X = 763</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{763 - 525}{119}

Z = 2

Z = 2 has a p-value of 0.977.

1 - 0.977 = 0.023

0.023 = 2.3% of standardized test scores are greater than 763.

You can learn more about the normal distribution at brainly.com/question/24663213

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Answer:

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Step-by-step explanation:

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hope this helps

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