Question

A torsion prescription balance has a sensitivity requirement of 4 mg. Explain how you would weigh 5 mg of hydromorphone hydrochloride with an error not greater than 5%. Use lactose as a diluent.

Answer 1

Answer:

75 mg of diluent

Step-by-step explanation:

Given data:

balanced sensitivity = 4 mg

percentage error = 5%

we know that measurement for  smallest quantity is given as

smallest quantity $= \frac{ balanced\ sensitivity}{percentage \ error}$

                           $= \frac{4\ mg}{0.05}$

                           = 80 mg

therefore minimum quatity to be measured is 80 mg

weight of hydromorphone hydrochloride is 5 mg

therefore we need to add diluent

amount of diluent is  = 80 mg - 5 mg = 75 mg

75 mg of diluent