Question

pyrite known as fools gold has the chemical formula FeS2. What is the weight fraction of iron Fe in pyrite

Answer 1

$\frac{55.845}{119.975}$ or 46.55%

Explanation:

 Formula of pyrite = FeS₂

 Problem:

Weight fraction of Fe in FeS₂

Solution

  Atomic mass of Fe = 55.845g/mol

  Atomic mass of S = 32.065g/mol

     To find the weight fraction of Fe in FeS₂:

     Weight fraction = $\frac{atomic mass of Fe}{molar mass of [tex]FeS_{2}$}[/tex]

   molar mass of FeS₂ = [55.845 + 2(32.065)] = 119.975g/mol

Weight fraction of Fe = $\frac{55.845}{119.975}$

    As a percentage, weight fraction of Fe = 46.55%

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