<u>Answer:</u>
Hence, Relation t is a function. The inverse of relation t is a function.
<u>Step-by-step explanation:</u>
We are given the relation as:
x: 0 , 2 , 4 , 6
y: -10 , -1 , 4 , 8
<em>Clearly from the y-values corresponding to the x-values we could see that each x has a single image (single y-value).</em>
Hence, the corresponding relation is a function.
Now we have to find whether the inverse of this relation is a function or not.
When we take the inverse of this function that is the y-values will behave as a pre-image and x-values as its image.
Hence we will see that corresponding to each y-value there is a unique image hence the inverse relation is also a function.
Hence, Relation t is a function. The inverse of relation t is a function.
So all you need to do if find the min of the function:
f(x)=0.04x^3-4x^2-176x
f'(x)=0.12x^2-8x-176
The only zero for this is x=84.105 <---first
Plug this into f(x) to get f(84.105)=-19300 <---second
Simply it as follows:
1 + 39 = 40
2 + 38 = 40 etc
18 + 22 = 40
19 + 21 = 40
There are 19 of these plus 40 itself . . .therefore 20 of them
20 x 40 = 800
And finally the last number not used, 20
Therefore 800 + 20 = 820
Solve for K by simplifying both sides of the equation, then isolate the variable.
K = 193
