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notka56 [123]
2 years ago
5

Write 8 as a product of primes. Use index notation

Mathematics
1 answer:
dimaraw [331]2 years ago
4 0

Answer:

2³

Step-by-step explanation:

8 = 2 × 2 × 2 = 2³

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A number is multiplied by 20, and that product is added to 5. The sum is equal to the product of 5 and 13.
liubo4ka [24]

Answer:

x = 3

Step-by-step explanation:

First, you will pick the first equation :

(x*20)

Then the next,

(x*20) + 5

Then the last equation,

(x*20) + 5 = 5*13

Then you solve

20x + 5 = 65

20x = 65 - 5

20x = 60

20x/20 = 60/20

x = 3

5 0
2 years ago
Dimensional analysis: How many atoms are in a kilogram of silver, if there are 6.02 x 10^23 atoms per mole and silver weighs 107
kondor19780726 [428]

Answer:

5.58×10²⁴ atoms.

Step-by-step explanation:

From the question given above, the following data were obtained:

1 mole of silver = 107.9 g

Number of atoms in 1 mole of silver = 6.02×10²³ atoms.

Number of atoms in a kilogram of silver =.?

Next, we shall convert 1 kg of silver to grams (g). This can be obtained as follow:

1 kg = 1000g

Therefore, 1 kg of silver is equivalent to 1000g.

Finally, we shall determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:

107.9 g of silver contains 6.02×10²³ atoms.

Therefore, 1000 g of silver will contain = (1000 × 6.02×10²³) / 107.9 = 5.58×10²⁴ atoms.

Thus, a kilogram of silver contains 5.58×10²⁴ atoms.

6 0
3 years ago
Perform the operation given that a = {−3, −2, −1, 0, 1, 2, 3}, b = {−4, −2, 0, 2, 4}, and c = {0, 1, 2, 3, 4}. (enter your answe
Ludmilka [50]
A ∩ c={0,1,2,3}

b ∪ (a ∩ c)={-4,-2,0,1,2,3,4}
7 0
3 years ago
How many times greater is 130,000,000 than 64,800,000?
insens350 [35]
\frac{130,000,000}{64,800,000} = \frac{1,300}{648} =\boxed {2.00617283951}
4 0
3 years ago
Solve system of equations 2x + 2y + 5z = 7 6x + 8y + 5z = 9 2x + 3y + 5z = 6
svet-max [94.6K]

Answer:

the values of x, y and z are x= 2, y =-1 and z=1

Step-by-step explanation:

We need to solve the following system of equations.

We will use elimination method to solve these equations and find the values of x, y and z.

2x + 2y + 5z = 7     eq(1)

6x + 8y + 5z = 9     eq(2)

2x + 3y + 5z = 6     eq(3)

Subtracting eq(1) and eq(3)

2x + 2y + 5z = 7

2x + 3y + 5z = 6

-    -       -        -

_____________

0 -y + 0 = 1

-y = 1

=> y = -1

Subtracting eq(2) and eq(3)

6x + 8y + 5z = 9    

2x + 3y + 5z = 6    

-     -      -          -

______________

4x + 5y +0z = 3    

4x + 5y = 3      eq(4)

Putting value of y = -1 in equation 4

4x + 5y = 3

4x + 5(-1) = 3

4x -5 = 3

4x = 3+5

4x = 8

x= 8/4

x = 2

Putting value of x=2 and y=-1 in eq(1)

2x + 2y + 5z = 7

2(2) + 2(-1) + 5z = 7

4 -2 + 5z = 7

2 + 5z = 7

5z = 7 -2

5z = 5

z = 5/5

z = 1

So, the values of x, y and z are x= 2, y =-1 and z=1

5 0
3 years ago
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