3 years ago

Plz help, will mark brainliest

1 answer:

4 0

Answer:

cccccccccccccccccccc

You might be interested in

gregori [183]

Answer:

54%

Step-by-step explanation:

6 0

3 years ago

vitfil [10]

If the -8 is under the square root, then...

$\displaystyle L = \lim_{x\to -3} \sqrt{x^2-8}\\\\L = \sqrt{(-3)^2-8}\\\\L = \sqrt{9-8}\\\\L = \sqrt{1}\\\\L = 1\\\\$

If the -8 is not under the square root, then...

$\displaystyle L = \lim_{x\to -3} \sqrt{x^2}-8\\\\L = \sqrt{(-3)^2}-8\\\\L = \sqrt{9}-8\\\\L = 3-8\\\\L = -5$

Either way, we replace x with -3 and simplify.

For more information, refer to the direct substitution rule for limits.

4 0

2 years ago

KengaRu [80]

Always congruent due to the way the shape is built

6 0

3 years ago

lord [1]

Answer:

Step-by-step explanation:

If a population is the entire school faculty, a sample of the population could be math teachers.

Always remember a sample is a part of the larger group.

7 0

2 years ago

SVETLANKA909090 [29]

yes

Step-by-step explanation:

3 0

3 years ago