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Artyom0805 [142]

3 years ago

10

Suppose a bank customer’s savings account balance grows at a steady rate. Which type of function would best represent the balanc

e of the savings account over time?
A) Linear function
B) Quadratic function
C) Exponential function
D) Both A and B

1 answer:

elena-s [515]3 years ago

7 0

Answer:

A) Linear function

Explanation:

grows at a steady rate.

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The horizontal line segment at the top of the polygon on the grid below is how many units long?

Ymorist [56]

Answer:

6 units long.

Step-by-step explanation:

Given:

A polygon drawn on a graph.

In order to determine the distance of the horizontal line at the top, we find the coordinates of the end points and then use distance formula to find the exact distance.

Let us label the polygon as ABCD as shown below. AB is the length of the horizontal line.

Coordinates of A are $(x_1,y_1)=(-3, 4)$ as seen in the graph.

Coordinates of B are $(x_2,y_2)=( 3, 4)$ as seen in the graph.

Now, distance formula for two points $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d_{AB}=\sqrt{(3-(-3))^2+(4-4)^2}\\d_{AB}=\sqrt{(3+3)^2+0}\\d_{AB}=\sqrt{36}=6\ units$

Therefore, the horizontal line at the top is 6 units long.

4 0

4 years ago

PLEASE HELP I WILL GIVE BRAINALIST

Oxana [17]

Answer:

Step-by-step explanation:

Original 873 New 781

The new went down by about 10.5%

873*10.5%= 91.67

873-91.67= 781.33

It decreased 10.5%

7 0

3 years ago

CAN SOMEONE HELP ME PLEASE ASAP!?

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Answer:

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3 years ago

Solve the differential equation. y' + 5xey = 0.

Gwar [14]

Answer:

The solution is $y = - ln(\frac{5}{2}x^{2} + C)$

Step-by-step explanation:

To solve the differential equation, we will find $y$

From the given equation, y' + 5xey = 0.

That is, $y' + 5xe^{y} = 0$

This can be written as

$\frac{dy}{dx} + 5xe^{y} = 0$

Then,

$\frac{dy}{dx} = - 5xe^{y}$

$\frac{dy}{e^{y}} = - 5x dx$

Then, we integrate both sides

$\int {\frac{dy}{e^{y}}} =\int {- 5x dx}$

$\int {e^{-y}dy }} =\int {- 5x dx}$

Then,

$-e^{-y} = -\frac{5}{2}x^{2} + C$

$e^{-y} = \frac{5}{2}x^{2} + C$

Then,

$ln(e^{-y}) = ln(\frac{5}{2}x^{2} + C)$

Then,

$-y = ln(\frac{5}{2}x^{2} + C)$

Hence,

$y = - ln(\frac{5}{2}x^{2} + C)$

8 0

3 years ago

Jane Marko buys a car for 43,900. in three years, the car depreciates 48% in value. how much is the car worth in three years ?

docker41 [41]

Let's take this step by step.

A car cost $43,900.

If it depreciates 48% in value in 3 years, we must find 48% of $43,900, and subtract that from its total value.

A 48% of $43,900 is:

$43,900 * 0.48 = $21,072

$43,900 - $21,072 = $22,828

The car is worth $22,828 in three years.

6 0

4 years ago

Read 2 more answers