Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
Step 1
Find the length of MD
we know that
The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle
so
In this problem
------> is the radius of a circle inscribed inside the triangle
we have that

therefore


Step 2
Find the length of DC
we know that
In the right triangle MDC
Applying the Pythagoras theorem

we have


substitute




When solving these proportions we just remember when moving a number from one side to the other if it started in the numerator it ends up in the denominator and vice versa.
I'll do it in two steps here for teaching purposes; it's not too hard to go directly to the answer.



19/38 = 1/2 (divided top and bottom by 19)
so
34 X 19/38
= 34 X 1/2
= 34/2
= 17/1
Answer
17/1 (or 17)
Answer:
a +d = a2
Step-by-step explanation:
-2 - (-9) =
-2+9=7
a + d = a2