<span>a fixed regular payment, typically paid on a monthly or biweekly basis but often expressed as an annual sum, made by an employer to an employee, especially a professional or white-collar worker.</span>
Answer:
24 cm
Step-by-step explanation:
The photo was 6 cm wide, and was made into 18 cm wide. Divide 18 with 6:
18/6 = 3
To solve for the length enlargement, multiply 3 with the length, or 8 cm:
8 x 3 = 24
24 cm is the length of the enlargement.
~
Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value =
= 5.29
Hello! $200 is the fixed amount. B doesn't have 200 as part of the problem, so B is eliminated. A is also out, because you add, not subtract. 100 is the amount of boots made, not the amount made per pair of boots. 100 would be the value of "x". The cost per day is $9,200, and 9,200 - 200 is 9,000. With 100 pairs of boots being made each day, 9,000/100 is 90. It would cost $90 per pair of boots made, with the variable "x" being beside it. The correct equation would be C(x) = 90x + 200. The answer is D.
For skewed data displays, the median is often a better estimate of the center of distribution than the mean because the former is unaffected by large numbers.
<h3>What is mean?</h3>
Mean refers to the average of set of two or more numbers.
Mean of a set having 'n' numbers = 
<h3>What is median?</h3>
Median refers to the middle-most value of a list of numbers, arranged either in ascending or descending order.
Median = 
Now,
- Since it takes the average of all the values in the data set, the mean is the most widely used measure of central tendency.
- Because it is unaffected by exceptionally big numbers, the median performs better than the mean when analyzing data from skewed distributions.
Hence, For skewed data displays, the median is often a better estimate of the center of distribution than the mean.
To learn more about mean and median, refer to the link:brainly.com/question/6281520
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