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Burka [1]
3 years ago
7

Gavin is subdividing land into two plots, where one plot is in the shape of a square and the other plot is in the shape of a rec

tangle. The square plot of land has a side length of 6x3 feet, and the rectangular plot of land has a length of 3x5 feet and a width of 7x2 feet. Use the properties of exponents to determine the expression that represents the area for each plot of land. Then analyze which plot of land has a larger area if x is 3.
Mathematics
1 answer:
marissa [1.9K]3 years ago
5 0
You have to multiply both of those
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Mia hired a moving company. The company charged
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She tips the movers $80
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3 years ago
For the pair of supply-and-demand equations, where x represents the quantity demanded in units of 1000 and p is the unit price i
Liono4ka [1.6K]

Answer:

7 and 6 respectively

Step-by-step explanation:

Firstly, we have to solve the equations simultaneously.

2x + 7p = 56

3x - 11p = -45

Multiply equation I by 3 and ii by 2

6x +21p = 168

6x - 22p = -90

Subtract the second from first to yield:

43p = 258

p = 6

Insert this in equation 1 where we have 2x + 7p = 56

2x + 7(6) =56

2x + 42 = 56

2x = 14 and x = 7

The equilibrium price is 6 and the equilibrium quantity is 7

8 0
3 years ago
What is the solution to the problem 2y+3=4y+2
yulyashka [42]

Answer:

y = 1/2

Step-by-step explanation:

<u>Step 1:  Solve for y</u>

2y + 3 = 4y + 2

2y + 3 - 2 - 2y = 4y + 2 - 2 - 2y

1 / 2 = 2y / 2

1/2 = y

Answer:  y = 1/2

8 0
3 years ago
Read 2 more answers
10-2x -x for x&lt;1 f(x) 3 + 4e^x-1 for x&gt; 1 f(x) be the function defined above. Is f continuous at x=1? Why or why not? Find
8090 [49]

it can not be a function because functions only have ONE input to each output

5 0
3 years ago
The ones with circles are the ones i need to do
TEA [102]

<em>1. </em>for (0,0) that would be at the very bottom at 0 is where you're point will be.

on (1,4) go over to the right to 1 nd then go up right below 5 and make a point.

for (2,8) go to the right to 2 and then move up to 8 and make a point.

for (3,12) go to the right 3 and then go up to 12 and make a point.

<em>2. </em>It makes a line.

<em>3. </em>(1,5)           (2,10)        (3,15)        (4,20)

chart on left is right but put parenthesis on both side like that ^

<em>4. </em>For Kens go to the right to 1 and go up to 5 and put a point. then go to 2 to the right and 10 up make point. then go 3 to right and 15 up and make a point. then go 4 to right and up 20 and make a point. Do same with other chart.


5 0
3 years ago
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