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3 years ago

Solve for x geometry

Mathematics

2 answers:

Nikitich [7]3 years ago

7 0

Answer:

X=19

Step-by-step explanation:

A full line must be 180 degrees and you already know that part of the line is 66 degrees. You do 180 minus 66 which gives you 114. That is the other unknown angle but it is asking for x, not the angle. You do 114 divided by 6 to get 19. Therefore, x=19.

AVprozaik [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

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Expand

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by moving

outside the logarithm.

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Divide each term by

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and simplify.

Tap for more steps...

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The result can be shown in multiple forms.

Exact Form:

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Decimal Form:

2.33829083

…

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Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

4 years ago

The polynomial below is perfect square trinomial of the form a^2 -2AB +B^2

guajiro [1.7K]

Answer:

In order to get this perfect square trinomial, the factored form will be (a - b)^2

Step-by-step explanation:

We know this because it follows the rule of perfect squares in which the ends are both squares and the middle term is -2 times each term.

5 0

4 years ago

On circle O below, the measure of FJ is 84º . The measure of GH is 76°.<br> What is the measure of

Vsevolod [243]

Given:

Measure of arc FJ = 84°

Measure of arc GH = 76°

To find:

The measure of angle HKJ.

Solution:

The image of the question is attached below.

Angles inside the circle theorem:

If two chords intersect inside a circle, then the measure of each angle is one half the sum of the measures of the intercepted arc and its vertical arc.

$$\Rightarrow m \angle G K H=\frac{1}{2}(m(a r \ G H)+m(a r \ F J))$