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Trava [24]
3 years ago
12

Write an explicit formula for an, the nth term of the sequence 112, -28, 7, ....

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

a_n=112\left(-\frac{1}{4}\right)^{n-1}

Step-by-step explanation:

<u>Geometric Sequences</u>

There are two basic types of sequences: arithmetic and geometric. The arithmetic sequences can be recognized because each term is found as the previous term plus a fixed number called the common difference.

In the geometric sequences, each term is found by multiplying (or dividing) the previous term by a fixed number, called the common ratio.

We are given the sequence:

112, -28, 7, ...

It's easy to find out this is a geometric sequence because the signs of the terms are alternating. If it was an arithmetic sequence, the third term should be negative like the second term.

Let's find the common ratio by dividing each term by the previous term:

\displaystyle r=\frac{-28}{112}=-\frac{1}{4}

Testing with the third term:

\displaystyle -28*-\frac{1}{4}=7

Now we're sure it's a geometric sequence with r=-1/4, we use the general equation for the nth term:

a_n=a_1*r^{n-1}

a_n=112\left(-\frac{1}{4}\right)^{n-1}

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<img src="https://tex.z-dn.net/?f=y%2B%20%20%5Cfrac%7B13%7D%7B4%7D%20%20%3D%20%28x%5E2-%20%5Cfrac%7B1%7D%7B2%7D%20%29%5E2" id="T
zhenek [66]

Answer:    \bold{y=\dfrac{1\pm \sqrt{4x+13}}{2}}

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and solve for y:

y+\dfrac{13}{4}=\bigg(x-\dfrac{1}{2}\bigg)^2\\\\\\x+\dfrac{13}{4}=\bigg(y-\dfrac{1}{2}\bigg)^2\rightarrow \text{(swapped the x's and y's)}\\\\\\\sqrt{x+\dfrac{13}{4}}=\sqrt{\bigg(y-\dfrac{1}{2}\bigg)^2}\rightarrow \text{(took square root of both sides)}\\\\\\\sqrt{\dfrac{4x+13}{4}}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(created common denominator in radical)}\\\\\\ \dfrac{\sqrt{4x+13}}{2}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(simplified radical)}

\pm \dfrac{\sqrt{4x+13}}{2}=y-\dfrac{1}{2}}\rightarrow \text{(divided both sides by}\ \pm )\\\\\\\dfrac{1}{2}\pm \dfrac{\sqrt{4x+13}}{2}=y\quad \rightarrow \text{(added}\ \dfrac{1}{2}\ \text{to both sides)}\\\\\\\dfrac{1\pm \sqrt{4x+13}}{2}=y\quad \rightarrow \text{(combined numerators)}

4 0
3 years ago
2. Three bells P, Q and R ring at intervals of 40, 48and 60 minutes respectively. If they ring together at 6.15 a.m. when will t
MAXImum [283]
They will ring again together at 10:15am. Because the common factor for 40, 48 and 60 is 240, which means 240 minutes, that equals to 4 hours. Hence 4 hours after 6.15am is 10.15am.

Hope this helps.
5 0
4 years ago
Four times the sum of a number is 2 is equal to 6
lapo4ka [179]

Answer:

4*(x+2)=6

Step-by-step explanation:

* is multiply four times is 4*

the sum of a number is 2 is (x+2) is equal to 6

6 0
3 years ago
Evaluate the following functions.
bezimeni [28]

Functions are written in terms of variables.  The value of the function given if x = -4 is 50

<h3>Functions and values</h3>

Functions are written in terms of variables. Given the function shown;

f(x) = 3x^2 - x

If the value of x is -4, hence;

f(-4) = 3(-4)^2 - (-2)

f(-4) = 3(16) + 2

f(-4) =48 + 2

f(-4) = 50

Hence the value of the function given if x = -4 is 50

Learn more on function here: brainly.com/question/25638609

#SPJ1

8 0
2 years ago
The equation of the piecewise defined function f(x) is below. What is the value of f(1)?
cestrela7 [59]

Answer:

-1

Step-by-step explanation:

First, we need to find which expression to use for f(1). The first function does not include 1, because it is <, and not \leq

The second functions includes 1, because it has a \leq, meaning greater than or equal to, so this is the function we must use.

-x^2

Plug 1 in for x

-(1^2)

Solve the exponent first

-(1)

-1

So, f(1)=-1

3 0
3 years ago
Read 2 more answers
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