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baherus [9]
3 years ago
11

What is the solution set of the equation x^2-3x-4=6

Mathematics
1 answer:
Oxana [17]3 years ago
4 0

Answer:

x = 5, x = -2

Step-by-step explanation:

x² - 3x - 4 = 6

Subtract: x² - 3x - 10 = 0

Find two numbers to factor: adds up to -3x, product is -10x²: -5x and 2x

Substitute: x² - 5x + 2x - 10 = 0

Factor: (x - 5)(x + 2) = 0

Solutions: x = 5, x = -2

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Please help! i cant solve it​
3241004551 [841]

a ≈ 5.2, B ≈ 50°, C ≈ 95°

Solution:

Given data:

A = 35°, b = 7, c = 9

Using cosine law,

a^{2}=b^{2}+c^{2}-2 b c \cos A

a^{2}=7^{2}+9^{2}-2 (7)(9) \cos 35^\circ

a^{2}=49+81-126 (0.82)

a^{2}=26.68

Taking square root on both sides.

a ≈ 5.2

Using sine law,

$\frac{\sin A}{a} =\frac{\sin B}{b}

$\frac{\sin 35^\circ}{5.2} =\frac{\sin B}{7}

Multiply by 7 on both sides.

$\frac{0.5735}{5.2}\times 7 =\sin B

Switch the sides.

Sin B = 0.772

B=\sin^{-1}0.772

B ≈ 50°

Sum of all the angles of a triangle = 180°

A + B + C = 180°

35° + 50° + C = 180°

85° + C = 180°

C = 180° - 85°

C = 95°

Hence a ≈ 5.2, B ≈ 50°, C ≈ 95°.

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