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3 years ago

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A 16-mb flash drive was sold on sale for $18.50. If this sales price was 81% of the original price, what was the original price?

1 answer:

storchak [24]3 years ago

4 0

Price of flash drive:-$18.50
sale price:-81%
so, price reduced :-81/100×18.50:-14.985
actual price:- $18.50+$14.985:-$33.485

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Each ruby in the crowns 1/2carat.How many total carats are the rubies?

Vitek1552 [10]

Answer:

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Step-by-step explanation:

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3 years ago

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Multiply or divide as indicated. <br><br> x 2 • x 5

WARRIOR [948]

Hi there!

${x}^{2} \times {x}^{5} = x {}^{2 + 5} = {x}^{7}$

We can also write is out entirely.
${x}^{2} = x \times x$
${x}^{5} = x \times x \times x \times x \times x$
${x}^{2} \times {x}^{5} = \\ (x \times x ) \times (x \times x \times x \times x \times x) = \\ x \times x \times x \times x \times x \times x \times x = \\ {x}^{7}$

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3 years ago

To find 19+(11+37)Lennon added 19 and 11 Then he added 37 to the sum What property did he use?

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3 years ago

A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in

Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

$\frac{dr}{dt} =\frac{1}{2}$ --- rate of the radius

$\frac{dh}{dt} =-\frac{1}{3}$ --- rate of the height

$r = 2$

$h = \frac{1}{3}$

Required

Determine the rate of change of the cone volume

The volume of a cone is:

$V = \frac{\pi}{3}r^2h$

Differentiate with respect to time (t)

$\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})$

Substitute values for the known variables

$\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)$

$\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{88}{63}$

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The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0

2 years ago

The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0.30, and the sample statistics

IrinaK [193]

Answer: 0.84

Step-by-step explanation:

let p be the population proportion of adults who smoked a cigarette in the past week.

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$H_a: p$

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The test statistic for proportion is given by :-

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Substitute all the values , we get

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Hence, the value of the test statistic = 0.84

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3 years ago