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Effectus [21]
3 years ago
10

Helppppppppppppppppp

Mathematics
1 answer:
valina [46]3 years ago
5 0
This is a simple "solve for x" equation.
5k-2k=12
3k=12
k=4
You should try doing some more on your own, as this will be coming up a lot in the future.
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What is the solution of the linear system of equations? <br><br><br> y=2x-3<br> y=2x+5
Akimi4 [234]

Hi Brainiac


y=2x-3

y= 2x+5


Ok we need to solve y=2x-3 for y

Now substitute 2x-3 for y in y=2x+5

y=2x+5

2x-3=2x+5

Add -2x

2x-3-2x=2x+5-2x

-3=5

Add 3

-3+3=5+3

0=8

No Solutions


I hope that's help:0

8 0
3 years ago
HELP HELP HURRY!!!!!
irinina [24]
If the entire ray is PQ, then all of those points lie on the ray.
4 0
3 years ago
Read 2 more answers
If x+1/x= 3, then prove that m^5+1/m^5= 123
alina1380 [7]

9514 1404 393

Explanation:

We can start with the relations ...

  \displaystyle\left(x+\frac{1}{x}\right)^3=\left(x^3+\frac{1}{x^3}\right)+3\left(x+\frac{1}{x}\right)\\\\\left(x+\frac{1}{x}\right)^5=\left(x^5+\frac{1}{x^5}\right)+5\left(x^3+\frac{1}{x^3}\right)+10\left(x+\frac{1}{x}\right)\\\\\textsf{From these, we can derive ...}\\\\x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(\left(x+\frac{1}{x}\right)^3-3\left(x+\frac{1}{x}\right)\right)-10\left(x+\frac{1}{x}\right)

  \displaystyle x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(x+\frac{1}{x}\right)^3+5\left(x+\frac{1}{x}\right)\right)\\\\x^5+\frac{1}{x^5}=3^5 -5(3^3)+5(3)\\\\=((3^2-5)3^2+5)\cdot3=(4\cdot9+5)\cdot3=(41)(3)\\\\=\boxed{123}

7 0
3 years ago
What num com between 4 and 6?
damaskus [11]

Answer:

5

Step-by-step explanation:

1,2,3,4,5,6

7 0
2 years ago
Read 2 more answers
X^2-25=0 Using factoring method
Tema [17]
Hello.

Move <span><span>−25</span><span>-25</span></span> to the right side of the equation by subtracting <span><span>−25</span><span>-25</span></span> from both sides of the equation.<span><span><span>x2</span>=25</span><span><span>x2</span>=25

</span></span>Take the square root of both sides of the equation to eliminate the exponent on the left side.
<span><span>
</span></span>The complete solution is the result of both the positive and negative portions of the solution.

Simplify the right side of the equation.

Rewrite <span>2525</span> as <span><span>52</span><span>52</span></span>.

Pull terms out from under the radical, assuming positive real numbers.The complete solution is the result of both the positive and negative portions of the solution.
<span><span>
</span></span>The complete solution is the result of both the positive and negative portions of the solution.

<span>Answer: x=5,−<span>5

Have a nice day</span></span>
6 0
3 years ago
Read 2 more answers
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