Answer:
B) 2pq
Explanation:
Hardy-Weinberg equilibrium refers to a model which explains the effect of evolution on the gene pool.
The model is based on the assumptions that if no evolutionary force like genetic drift, natural selection and many other will act on the population and therefore the gene pool (gene frequency and the genotypic frequency) of a populations remains in equilibrium or constant throughout the generations.
The genotypic frequency in the model is calculated by
P² = genotype of a homozygous dominant trait
q² = genotype of a homozygous recessive trait
2pq = genotype of heterozygous trait.
Thus, P²+2pq+q²=1
In the given question, since the population is in equilibrium that is no evolutionary force is acting, therefore, the genotype frequency remains the same that is the frequency of Aa will remain same that is 2pq even after 100 generations.
Thus, Option-B is the correct answer.
Let us solve first the
phenotype of this problem.
Starchy grain = AA (dominant)
Sugary Corn = aa (recessive)
AA x aa = AaAa ; AaAa
<span> A A</span>
<span>a Aa Aa</span>
<span>a Aa Aa</span>
The result of the cross is
that the progeny will become heterozygous.
<span>If there is 58 progeny
sugary, there will also be 58 starchy. It is 50%.</span>
Answer: D just took the test
Explanation:
Answer:
its C
Explanation:
i do AP bio so this is something learned a long time ago also im a straight A student so yeah
Answer:
See explanation
Explanation:
We inherit our blood groups from both parents. Our blood type is controlled by a single gene. This gene displays 3 different allelic pairs which must include A, B or O. A child is expected to receive one of the three possible allelic pairs from each of the both parents. This means that there are six possible genotype and four possible phenotype for the child.
Given that Christopher's parents (Andersons) are AB and O,Christopher can have a B blood group.
Given that John's parents (Browns) are A and O, it explains how John can have blood group A.
Given that The Christiansons are A and AB, they can give birth to Robin whose blood group is AB.
Since the Dietrichs are O and O, the only possible blood group of their child is O, hence they are definitely the parents of Jane.