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yaroslaw [1]
2 years ago
8

A triangle is 6 centimeters long and 4 centimeters high. What is the area of the triangle?

Mathematics
1 answer:
schepotkina [342]2 years ago
6 0
24cm
You multiply 6*4=24. Hope this helps! Also can u mark brainliest i need one more :)
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Use the following information for problems 1 – 3. Suppose you sign a contract for an annual salary of $50,000 with a guaranteed
erik [133]

Initial salary =  $50,000 .

Rate of raise = 5% each year.

Therefore, each next year salary would be 105% that is 1.05 times.

5% of 50,000 = 0.05 × 50000 = 2500.

Therefore raise is $2500 each year.

According to geometric sequence first term 50000 and common ratio 1.05.

Applying geometric sequence formula

a_n = ar^{n-1}

1) a_n = 50000(1.05)^{n-1}

2) In order to find salary in 5 years we need to plug n=5, we get

a_5 = 50000(1.05)^{5-1}= 50000(1.05)^4

= 50000(1.21550625)

<h3>=$60775.3125.</h3>

3) In order to find the total salary in 10 years we need to apply sum of 10 terms formula of a geometric sequence.

S_n = \frac{a(1-r^n}{1-r}

Plugging n=10, a = 50000 and r= 1.05.

S_10 = \frac{50000(1-(1.05)^{10}}{1-1.05}

S_10 = \frac{50000(0.050)^{10}}{0.05}

= 628894.62678.

<h3>Therefore , you will have earned $ 628894.62678 in total salary by the end of your 10th year.</h3>



7 0
2 years ago
Use the FOIL method to find the product. (8a − 8)(4a + 1)
melomori [17]

44a - 1

Im pretty sure


7 0
2 years ago
Please help marking brainliest QUICK
blsea [12.9K]

Answer:

50 lbs.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi
rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a  statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

P(9

Recall Chebyshev's inequality that

P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\

Comparing with the Ii equation which is appropriate here we find that

\mu =14.5

Next what we find is

k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071

Thus from the given information we find that

\mu = 14.5\\\sigma = 5.071\\k = 1.084

5 0
3 years ago
What is the slope of the line through the points (-2, -1) and (4, 3)? ​
Natalka [10]

Answer:

#2 option: \frac{2}{3}

Step-by-step explanation:

slope=\frac{rise}{run} =\frac{y^2-y^1}{x^2-x^1}

\frac{3-(-1)}{4-(-2)}=\frac{-4}{-6} =\frac{-2}{-3} =\frac{2}{3}

=  \frac{2}{3}

8 0
1 year ago
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