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Lady_Fox [76]
3 years ago
14

A circle has the equation 2x2+12x+2y2−16y−150=0.

Mathematics
1 answer:
astra-53 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

hello :

2x²+12x+2y²−16y−150=0

divide by 2 : (x²+6x)+(y²-8y)-75 =0

(x²+6x+9)-9+(y²-8y+16)-16-75 =0

(x+3)²+(y-4)² =10²

The coordinates of the center are (−3,4), and the length of the radius is 10 units.

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Work out<br> a) 4 1/3x6 <br> B) 2 3/5 x 3 1/3 <br><br><br> Give Answers as mixed numbers
anygoal [31]

Answer:

Solution of the given expression is 26

Solution of the given expression is 8.67

Step-by-step explanation:

Given:

a] 4\frac{1}{3} \times 6

b] 2\frac{3}{5} \times 3\frac{1}{3}

Find the solution;

Computation:

a] 4\frac{1}{3} \times 6

Step 1 ;

Changed mixed fraction into simple fraction

⇒ 13/3 x 6

Step 2 ;

⇒ 13 x 2

26

Solution of the given expression is 26

b] 2\frac{3}{5} \times 3\frac{1}{3}

Step 1 ;

Changed mixed fraction into simple fraction

⇒ (13/5) x (10/3)

Step 2 ;

⇒ 130 / 15

8.67

Solution of the given expression is 8.67

4 0
3 years ago
Please help! I put a screenshot :) I would like<br> a detailed answer please :) 55 points :)
seropon [69]

Method A: If we count, we see that the answer is 31.

Method B: 19 - -12 = 31. We can even do -12 - 19 and we'll get the same answer: -31, and the absolute value of -31 is 31.

Both methods will give you the same answer.

6 0
3 years ago
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Solve the system using substitution. Show all work.
Brrunno [24]

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4 0
3 years ago
18x^2+21x-9 I need to figure out how to work this problem
shtirl [24]
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3 0
3 years ago
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Why does (x-2)^2+9=0 have no real solutions?
alex41 [277]

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ± \sqrt{-9}

\sqrt{-9} yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to \sqrt{-9} are said to be imaginary, that is ± 3i

where i = \sqrt{-1}

If interested investigate further.

7 0
3 years ago
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