The average rate of change of h(x) in the closed interval [ a, b ] is
Here [a, b ] = [ - 2, 2 ], thus
f(b) = f(2) = × 2³ - 2² = 1 - 4 = - 3
f(a) = × (- 2)³ - (- 2)² = - 1 - 4 = - 5
average rate of change = = =
Answer:
Step-by-step explanation:
Given function is,
f(x) = 
If the given function is vertically stretched by a scale factor of 
Or 1.5,
Transformed function will be,
h(x) = ![\frac{3}{2}[f(x)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bf%28x%29%5D)
h(x) = 
Further function 'h' is shifted 1 units upwards,
g(x) = h(x) + 1
g(x) = 
Domain of the function → x ≥ 0 Or [0, ∞)
Range of the function → y ≥ 1 Or [1, ∞)
Transformations done → Parent function f(x) is vertically stretched by a scale factor of then shifted 1 unit upward.
Square root (x + 8) -6 = x
square root (x + 8) = x -6
x^2 + 16x + 64 = x^2 -12x + 36
28x = 48
x =
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1.7142857143
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None of the above
Answer:
Step-by-step explanation:
The distance around a rectangle or a square is as you might remember called the perimeter. The distance around a circle on the other hand is called the circumference (c).
circle diameter radius
A line that is drawn straight through the midpoint of a circle and that has its end points on the circle border is called the diameter (d)
Half of the diameter, or the distance from the midpoint to the circle border, is called the radius of the circle (r).
The circumference of a circle is found using this formula:
C=π⋅dorC=2π⋅r
Step-by-step explanation:
First u have to do the work of bracket and the solve
