Answer:
1.25 x 10^2 times greater.
or
125 times greater.
Step-by-step explanation:
The required ratio is 5 x 10^7 / 4 x 10^5
= 5/4 * (10^7 / 10^5)
= 1.25 x 10^2 greater.
In a normal distribution, the median is the same as the mean (25.3). The first quartile is the value of

such that

You have

For the standard normal distribution, the first quartile is about

, and by symmetry the third quartile would be

. In terms of the MCAT score distribution, these values are


The interquartile range (IQR) is just the difference between the two quartiles, so the IQR is about 8.8.
The central 80% of the scores have z-scores

such that

That leaves 10% on either side of this range, which means

You have

Converting to MCAT scores,


So the interval that contains the central 80% is

(give or take).
A "solution" is where the graph crosses the
x-axis so while the quadratic has no real solutions, the straight line passing through it does as it intersects the x-axis at x=-2.
Hope this helps! :)
Answer:
1. C
2. D
3. B
4. C
5. A, B, D
6. B
7. A
8. B, D
9. A, C, D
10. D
Just took it and got 100% ;)
Answer:
Answer is d because no is a polynomial