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2 years ago

Solve for the variable W over 15 = 3 over 15

Mathematics

1 answer:

Anvisha [2.4K]2 years ago

5 0

W/15 = 3/15
cross multiply 15 by 3
15 x 3 = 45
then divide 45 by 15
45 x 15 = 3

therfore W = 3

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Rick and Betty are going to Virginia. It is an 8 hour trip. Rick gets. 50 mile head start and drives at a rate of 55 mph. Betty

maw [93]

The equations y=55x+50 and y=65x represents Rick's and Betty's trip.

Step-by-step explanation:

Given,

Head start of Rick = 50 miles

Speed of Rick = 55 mph

Let,

x be the number of hours

y be the total miles

Distance covered by Rick in x hours = Speed * Time + Head start

y = 55x + 50

Speed of Betty = 65 mph

Total miles = Speed*Time

y=65x

The equations y=55x+50 and y=65x represents Rick's and Betty's trip.

Keywords: variable, addition

Learn more about variables at:

#LearnwithBrainly

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2 years ago

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

Answer-

The polynomial function is,

$y=x^4-10x^3+38x^2-64x+40$

Solution-

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

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3 years ago

The marijority of the population in the United states _________.

Nadusha1986 [10]

It should be C english :)

6 0

2 years ago

Write the ratio for each: Sin=?/? Cos=?/? tan=?/?

Sav [38]

Sin=opposite side/hypotenuse
cos=adjacent side/hypotenuse
tan=sin/cos or opposite/adjacent

4 0

2 years ago

For the cereal box, name each of the following

zaharov [31]

Answer:

AB , AD , EF , EH all intersect AE ⇒ answer (c)

Step-by-step explanation:

∵ AE segment passing through A and E

∴ Each segment passing through A and E intersects AE

∴ AB intersects AE at A

∴ AD intersects AE at A

∴ EF intersects AE at E

∴ EH intersects AE at E

∴ The answer is (c)

Step-by-step explanation:

8 0

3 years ago