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dlinn [17]
3 years ago
15

Two parallel lines are crossed by a transversal.

Mathematics
2 answers:
tigry1 [53]3 years ago
6 0

Answer:

118

Step-by-step explanation:

bogdanovich [222]3 years ago
4 0

Answer: b=52

Step-by-step explanation:

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6(2x - 5) – --3(9 + 4x)
miskamm [114]

Answer:

-27-12x

Step-by-step explanation:

6(2x - 5) – --3(9 + 4x)

-3(9+4x)

-3 x 9 - 3 x 4x

-27-12x

6 0
3 years ago
Solve the inequality:
olya-2409 [2.1K]

Answer:

8 - 2x <4 gives us x>2

|x-8| >22 gives us (-inf, -14) and (30,inf)

|x+5| < 4 gives us (-9,-1)

Step-by-step explanation:

Inequalities differs from equalities in that they return a range of values for x and not a single value (case of equalities)

The first one

8 - 2x <4 if you subtract every side 8, you will get -2x<-4

Next divide every side with -2, since its a negative number you have to change the orientation of the inequaiity, thus we have x>4/2, x>2

The second

|x-8| >22, it has to be treated as this. -22>x-2>22 which can be treated as two single inequalities, -22>x-8, and the other, x-8>22. The fist gives you x<-14, and the other x>30, two non intercepting ranges, so your range will be (-inf, -14) and (30, inf)

The third

|x+5| < 4 if you apply the same steps from above, you will have the following  -4<x+5<4 This results in two intercepting ranges, giving you the range (-9,-1)

4 0
4 years ago
Probability of numbers divisible by 9 from numbers 1-100?
quester [9]
11
(9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99)
Those numbers divisible by 9 are the multiple of 9; thus need to know how many multiples of 9 there are between 1 and 100:

100 ÷ 9 = 11 r 1 ÷ last multiple of 9 is 11 × 9 (= 99)
→ There are 11 - 1 + 1 = 11 numbers between 1 and 100 which are divisible by 9.

(They are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.)
7 0
4 years ago
I give brainliest if it is correct
Georgia [21]

Answer:

172 yd²

Step-by-step explanation:

4 0
2 years ago
Find the value of n<br> 6+n=1+6
NeX [460]
N = 1 because 1 + 6 = 7 so what plus 6 = 7
7 0
3 years ago
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